How DO YOU prepare .01 M NaOH?
0.01M NaOH is 0.01 moles of NaOH in 1L of water. The molecular weight of NaOH is 23 + 1 + 16 = 40g/mole, and 0.01 moles would have a mass of 0.40g (0.01moles x 40g/mole).
So, adding 0.40g NaOH to 1L water gives a solution of 0.01M NaOH.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of Solution Volume of Solution required = 5.00L We can say therefore that: Number of Moles of NaOH needed to prepare the solution = Concentration of NaOH * Volume of Solution required Therefore: Number of Moles of NaOH needed to prepare the solution = 0.025M * 5.00L = 0.125moles From this we can say that 0.125 moles of NaOH are needed to prepare a…