Math and Arithmetic
Algebra
Geometry

# How big is 250 sq ft in length and width?

789

Depends

length-25ft

width-10ft

length - 125ft

width - 2ft

length - 50ft

width- 5ft

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## Related Questions

The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.

Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.

Perimeter = 2(length + width) &rarr; width = perimeter &divide; 2 - length length = 1 foot &rarr; width = 70 ft &divide; 2 - 1 ft = 34 ft; length = 2 feet &rarr; width = 70 ft &divide; 2 - 2 ft = 33 ft.

area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft

Just multiply the length by the width to get square feet. 100x100=10,000sq ft

Runway: 25R Length x Width: 12923 ft x 150 ft Runway: 07L Length x Width: 12923 ft x 150 ft Runway: 25L Length x Width: 11095 ft x 200 ft Runway: 24R Length x Width: 8926 ft x 150 ft Runway: 24L Length x Width: 10885 ft x 150 ft Runway: 07R Length x Width: 11095 ft x 200 ft Runway: 06R Length x Width: 10885 ft x 150 ft Runway: 06L Los Angeles Ramp/Taxi: 131.45

From here, it appears that the length is double the width.

The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.

Length-300 ft to 5 miles Width quarter-inch

The area formula is: Area = length x width Let: length = 40 ft width = 50 ft Then: A = 40 ft x 50 ft = 2000 ft&sup2;

The length of the rectangle that has the area of 120 ft and the width of 8 ft is 960 ft that is the correct answer 960 ft

Assuming Width &lt;= Length then the width can be any positive value less than sqrt(270) feet = 16.43 feet (approx). Width = 15 ft goes with Length = 270/15 = 18 feet Width = 10 ft with Length = 270/10 = 27 ft Width = 0.0001 ft with Length = 270/0.0001 = 2700000 ft etc.

It is 94 feet in length, and 50 feet in width that's for NBA, for high school and college its 84 feet in length and 50 ft, in width

length = 1380/width or width = 1380/length Unless a length or width is given it's impossible to give an accuratee answer.

Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft

Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft &rArr; length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: &rArr; (16ft - width) x width = 48 sq ft multiplying out and rearranging: &rArr; width2 - 16 x width + 48 = 0 factorizing: &rArr; (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: &rArr; width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.

Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in

By multiplying its length to its width. Area= length x width

Multiply the length by the width. i.e. 10' wide x 25' long... has an area of 250 sq. ft.