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Energy Conservation

How can you calculate the generated heat produced by any heating coil by appling 1 kW of electrical energy for one hour?


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June 29, 2014 10:22PM

Applying a power of 1 kW produces an energy of one kilowatt-hour or 3.6 million watt-seconds, equal to 3.6 million Joules or 3.6 MJ.

4.2 Joules is 1 calorie, so divide by 4.2 to convert to calories and the answer is 857 kilocalories. So 857 litres of water could be raised by 1 degree C. Alternatively 85.7 litres would be raised by 10 degrees, etc.