(7 + 5 - 9) x 8 = 24
3! = 6.
4*3*2 = 24 of them.
5! / 4 - 2 * 3
None.
-1230
5*4+3+2
3! = 6.
4*3*2 = 24 of them.
5! / 4 - 2 * 3
8
(4+5-6)x8=24
If you want 4-digit numbers, there are 24 of them.
None.
-1230
One possible way to make 2000 using numbers between 1 and 9 once is: 9^3 − 8 × 7 − 6 × 5 × 4 − 3 × 2.
-9
8 * 1* 2^0 * 4^0=8