Math and Arithmetic
Algebra
Prime Numbers

# How can you tell if 342 is divisable by 3?

The sum of its digits is a multiple of 3, so 342 is a multiple of 3.

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## Related Questions

Yes 345 is divisable by 3 because when u divide it by 3 the answer is 115.

It is divisible (not divisable) by 1, 3, 9, 27.

The digits of a multiple of three sum to a multiple of three. for 342, 3+4+2 = 9 Since 9 is a multiple of three, 342 is as well. It is the product of 114 and 3

Divide it by 3. In this case, 342 IS divisible by 3, because we get 114 instead of a fraction.And the quicker way is: Add the digits: 3+4+2 = 9If the sum of digits is divisible by 3 then the number is divisible by 3. 9 is divisible by 3 so is 342.

102,068,001 is NOT a prime number. It is evenly divisable by 3. A prime number is only evenly divisable by 1 and itself. It is also divisable by 9.

Yes because there is 9, 18, 27, ect. including 3 itself.

it cannot be divisable by 5 and 9 but it can be divisable by 2,3,4,6,41,28,and 21

because 6 is also divisiable by 3... just alike all numbers that are divisable by 162 are divisable by 6 AND 3

No, 6 is divisable by 3 but not divisable by 9, same goes for 12, 15 and 24 ... so on.

It is 2754 with a remainder of 2.

Yes but it will have a remainder of 3

The prime factors are 342 are 2, 3, 3, and 19. Thus the numbers 342 is divisible by are 1, 2, 3, 6, 9, 18, 19, 36, 38, 57, and 342.

No, 22,791 is divisable by 3. 22,791 / 3 = 7597

No. It would have to be divisible by 2 and 3 and it is not divisible by 3.

Not evenly because there will be a remainder of 1

5+6=11 which is not divisible by 3, then 56 is not divisible by 3

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