The charged particle moves like it accelerated around the field and along the field:
F= - qV.B + qVxB = ma = -qvbcos(angle) + nqvbsin(angle) where n is perpendicular to the the plane of V x B. The acceleration a= F/m = (-cos(angle) + n sin(angle))qvB/m is a quaternion acceleration consisting of a scalar and a vector.
The motion of the particle is an ellipse inclined to the direction of the field. If the angle is 90 degrees, the ellipse is a circle and is perpendicular to the field direction.
So the forces acting on these charges have to be compared. Is it so? The famous formula meant to know about the force acting on a moving charged particle entering into a magnetic field is given as F = B q v sin@ Here @ is the angle inclined by the moving particle with the magnetic field. In the first case @ = 90 deg. As sin90 = 1 the force is Bqv. In second case @ = 30 deg. As sin 30 = 1/2 the force is 1/2 Bqv. Hence the force on the latter will be half of that on the earlier one.
If an electron enters a magnetic field parallel to the field lines (i.e., parallel to B), it will not experience any deflection or force due to the magnetic field. This is because the force on a charged particle moving parallel to a magnetic field is zero.
The kinetic energy gained by the particle due to the potential difference can be calculated using the formula KE = qV, where q is the charge and V is the potential difference. The kinetic energy can then be equated to the work done by the magnetic field, given by W = qvBd, where v is the velocity, B is the magnetic field, and d is the distance traveled in the magnetic field. Combining these equations can help determine the speed of the particle as it enters the magnetic field.
The man forgot his parachute in his backpack.
if charge particle is in motion ,then it has magnetic field
a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be
A mass shot at an angle in a uniform gravitational field and a charged particle shot at an angle through a uniform electric field. The mass and the particle in their respective situations will both follow the path of a parabola (both will have a constant velocity perpendicular to the field and a constantly changing velocity parallel to the field).
when a charged particle is moving with some velocity it produces some magnetic field. If we place that charged particle in presence of external magnetic field it gets affected by that external field.
It would be smaller. The force on the particles will be the same. However, their bigger mass (inertia) will mean that their sideways acceleration is less than for lighter particles. They travel in a larger arc
In a cyclotron, the charged particle is accelerated by the oscillating electric field between the dees. When the particle enters the gap between the dees, the electric field is zero, but a magnetic field causes the particle to rotate in a circular path and gain energy each time it crosses the gap due to its velocity being increased by the electric field before entering the gap.
1) Pathway of a charged particle when it enters a magnetic field... 2) Pendulum oscillations. (simple harmonic motion)
When a charged particle moves perpendicular to a magnetic field, it experiences a magnetic force that acts perpendicular to both the particle's velocity and the magnetic field direction. This force can cause the charged particle to move in a circular path due to the magnetic field's influence on its direction of motion.
So the forces acting on these charges have to be compared. Is it so? The famous formula meant to know about the force acting on a moving charged particle entering into a magnetic field is given as F = B q v sin@ Here @ is the angle inclined by the moving particle with the magnetic field. In the first case @ = 90 deg. As sin90 = 1 the force is Bqv. In second case @ = 30 deg. As sin 30 = 1/2 the force is 1/2 Bqv. Hence the force on the latter will be half of that on the earlier one.
Depending on the direction of the magnetic field and the charge on the particle, the charge would move in a circular fashion either clockwise or anticlockwise depending on the circumstance. Using the right hand palm (push) rule, find the direction of the force (palm) and the charge continues on that path in a circular motion. If the particle leaves the field, it continues in that direction traveling in a straight line unless under other influences.
If an electron enters a magnetic field parallel to the field lines (i.e., parallel to B), it will not experience any deflection or force due to the magnetic field. This is because the force on a charged particle moving parallel to a magnetic field is zero.
The kinetic energy gained by the particle due to the potential difference can be calculated using the formula KE = qV, where q is the charge and V is the potential difference. The kinetic energy can then be equated to the work done by the magnetic field, given by W = qvBd, where v is the velocity, B is the magnetic field, and d is the distance traveled in the magnetic field. Combining these equations can help determine the speed of the particle as it enters the magnetic field.
When a charged particle is moved along an electric field line, it will experience a force in the direction of the field line. The work done on the particle depends on the distance it moves and the strength of the field. If the particle moves perpendicular to the field lines, then no work is done by the field.