You need the Ksp of copper sulphide. From that you can use the equation for solubility product - Ksp = [Cu2+].[S-] where the Cu2+ term becomes 25M.
Copper(II) chloride is already a compound; its formula is CuCl2
The chemical formula (not equation) of copper(II) chloride is CuCl2.
They are identical - bonding two elements to form a binary compound. The only difference is that copper can be found as copperII or copperIV so it's correct to specify which one, that's all. Save with Pb (lead) and other unique metals/nonmetals.
The solubility of CuCl2 in water is 75,7 g/100 mL at 25 0C.
The Transition metals can have variable charges depending on what they are bonded to. In this example the Copper atom is deficient by two electrons one for each Chlorine atom.
CuCl2 is Copper (II) chloride
Since copper (I) chloride has only limited solubility in water I will assume you mean copper (II) chloride, CuCl2. Then the ions will be Cu2+ and Cl-.
CuCl2 + Fe = FeCl2 +Cu
CuCl2 is the product.
CuCl2 + Mg ------> MgCl2 + Cu
Na2O + CuCl2 --> 2 NaCl + CuO
CuCl2 is the chemical formula of cupric chloride.
In the chemical formula CuCl2 it is obvious for a neutral ionic substance that copper has a +2 charge, since Cl only comes in -1 charge, but in the stock name of copper chloride, it is unclear whether it is CuCl2 you are talking about or CuCl, which has a +1 Copper, thus in the name, the charge of the metal is differentiated by the roman numeral in parenthesis after the metal. This stock system (using numerals) is much easier to read than the previous traditional system of naming the higher charge metal with the -ic ending and the lower charged metal with the -ous ending, where CuCl2 and CuCl would be cupric chloride and cuprous chloride, respectively.
M = 134.45 g/mol (anhydrous) CuCl2
Add 2 to CuCl2 and CuCl.Now it is balanced.
Cu + Cl2 -> CuCl2
cu(II) + 2agcl --> 2ag+cucl2
CuO + 2HCL - CuCl2 + H2O
Under normal conditions CuCl2 can exist in either a solid state or in aqueous solution.