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In the simplest terms, the club with the better regular season record (their win-loss percentage) receives home field advantage (I want to say this has been the case since 1975). Which means that a wild-card team will never play at home in the first or second round of the playoffs because they always face a higher ranked team. For that matter, it is unlikely they will host any playoff game, unless the fifth and sixth seeded teams (the two wild-card teams) were to end up playing each other for the conference championship.

Here is a lot more information from NFL.com dealing with tiebreakers (used to determine home field at the end of the season). It might look a little overwhelming, but most of the rules are never needed (as you'll read, technically a coin toss could decide venue, but that's pretty unlikely). Enjoy.

http://www.nfl.com/standings/tiebreakers

Well, its not the team with the better record that plays at home on wildcard weekend, but the team that won their division. A #4 seed will have home field advantage over a wildcard 5 seed, even if the 5 seed had a better record, as happened in the wildcard game between the patriots and jaguars during wildcard weekend 2006, for the 2005 season.

The term "wild card round" is somewhat of a misnomer. In the first round of the playoffs, there are two divisional champions and two wild card teams. The highest-seeded division champion hosts the lowest-seeded wild card team, and the other division winner hosts the other wild card team.

The winners of these games go on to play two more division winners -- the top two seeds in each conference, who earned a "bye" and got to skip to the second round of the playoffs. Once again, the highest seeded division winner plays the lowest remaining seed.

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Q: How do they determine where the NFL Wildcard games are played?
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