there could be a part in it like this:
int num, digit;
int count [10];
do {
digit = num%10;
num != 10;
++count[digit];
} while (num);
see the program
Reference:cprogramming-bd.com/c_page2.aspx# reverse number
No, 3.4 is not an integer. It is a rational number and a real number, but not an integer.
A rational number which is an integer can be simplified to a form in which the denominator is 1. That is not possible for a rational number which is not an integer.
The number 14.5 is a decimal and not an integer. An integer is any number which is a whole number.
Every integer is a rational number.
It depends, if a number with positive integers is greater than the number with the negative integer therefore the sum will be in positive integer. And if the number with positive integer is less than the number with the number with negative integer then the sum will be in negative integer.
No, it is a decimal number.
Unless the integer is fractional it is not an irrational number.
Assuming the number is represented by a decimal integer, initialise a counter to zero, then repeatedly divide the number by 10 and until the number is zero. After each division, examine the remainder. Each time the remainder is zero, increment the counter. If the number is represented by a decimal float, repeatedly multiply by 10 until the value is an integer, then perform the previous algorithm.
The charAt function returns the number of occurrences of a specified character in the input string.
A decimal number is not an integer. An integer is a number that is not a fraction, and decimal numbers are decimal fractions.