The answer depends on the shape of the pool. If the pool is of uniform depth, then its volume is the surface area times the depth. If the surface area is measured in square feet, and the depth is measured in feet, then the volume is in cubic feet.
1 cubic foot = 6.2288 Imperial gallons.
how do i calculate the volumn of backwash in a pool
We need depth to calculate that
To calculate you would need the height of the pool. (pi)(radius2)(height)/231 = gallons
This pool holds up to 13,460 gallons of water. (this would fill it to the very top)
Start taking the water out of the pool with a 5 gal bucket...
First, determine how many gallons of water your pool holds. Then use this formula to convert gallons to cubic feet: gallons x 0.133681 = cubic feet
Pool capacity in gallons divided by fill time in hours equals fill rate in gallons per hour (gal / hr = gal/hr).
There is NO way to calculate this without knowing how deep the pool is filled!
A 21' pool that is 48" high should have 10,407 gallons of water (approx). To calculate the gallons in a round swimming pool use this formula: Length x length x average depth x 5.9 = gallons of pool So in your case 21 x 21 x 4 x 5.9 = 10,407 gallons
length(M) x width(M) x average depth(M) you will get pool volume in cubic meter. convert it in to gallons or any other unit
You must have the depth or average depth to calculate.
No way to calculate as you didn't say how deep it is.
First you have to figure the number of gallons in the pool. Go to: www.poolsandspachemicals.co.uk. Fill in your pool information and the site will calculate the number of gallons. Next examine the instructions on your algaecide and it will tell you how many ounces of algaecide to use per 10,000 gallons of water per week.
Measure the diameter and depth of the pool, in feet. Gallons = 5.8752 x (diameter x diameter x depth). That will work if the bottom of the pool is flat. If the bottom slopes, then it's going to be a lot more complicated.
An 18000 gallon pool has approximately 8 gallons per square foot. The actual amount of water varies based on the depth of the pool itself which is used to calculate cubic feet or volume.
It's a common mistake, but you must first find the volume of the pool. Calculate the volume of the pool by surface area X average depth. This will give you the cubic footage (approx.) in the pool. Ft3 X 7.48 (gal/ft3) will give you gallons in pool (approx.).
There are 7.48 gallons per cubic foot of interior space. You have to calculate the volume, in cubic feet, and then multiply that result times 7.48.
How large is the pool? In ground or above ground? Shape? Above ground is easier to calculate. I have an oval above ground pool which is 18 x 38. It holds approx. 15,000 gallons. To get an accurate answer, you need to be far more specific.
This site should help: http://www.backyardcitypools.com/swimming-pools/Pool-Volume-Calculate.htm .
This pool can contain up to 22,442 gallons of water.
You measure the dimensions of the pool using some measurement units (feet, yards, metres). Then, using geometry, you would need to calculate the volume of the pool in some appropriate units (cubic feet, cubic yards, cubic metres). these measures can then be converted to gallons using standard conversion factors. However, you need to be careful whether you want US gallons or Imperial gallons since these are not the same - one more reason why the "customary" system of measurement is rubbish and near obsolete.
To calculate the volume in gallons of a round pool, do the following calculation: diameter x diameter x depth x 5.9 Example: 28ft x 28ft x 4ft x 5.9 = 18,502.4 gallons