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This depends on the mass of calcium carbonate.

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8y ago
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12y ago

- log(1 M HNO3)

= 0 pH

Off the scale, but a concentrated and strong acid. You can be off the 1 to 14 pH scale.

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13y ago

1.60

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Q: How much 2.5 molarity of HNO3 is required to react the CaCO3?
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What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?

Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3


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Two steps. Find molarity of nitric acid and need moles HNO3.Then find pH. 1.32 grams HNO3 (1 mole HNO3/63.018 grams) = 0.020946 moles nitric acid ------------------------------------- Molarity = moles of solute/Liters of solution ( 750 milliliters = 0.750 Liters ) Molarity = 0.020946 moles HNO3/0.750 Liters = 0.027928 M HNO3 ----------------------------------finally, - log(0.027928 M HNO3) = 1.55 pH ==========( could call it 1.6 pH )


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