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How do you calculate the maximum mass of aluminium chloride that can be formed when reacting 15.0g of aluminium with 2.0g chlorine?
Wiki User
∙ 12y ago
2 Al + 3Cl2 --Ã 2AlCl3 so 2 moles of Aluminium atoms react with 3 moles of chlorine molecules or 1 atom of Al reacts with 3 atoms of chlorine. Aluminium has an atomic weight of 27 and Chlorine atoms 35.5. Multiplying by Avagadro's number 1 mole of Al atoms reacts with 3 moles of chlorine atoms.
So 27 g of Al reacts with 106.5 g Chlorine (3 x 35.5) to produce 133.5 g AlCl3
15g Al = 15/27 = 0.5556 moles (4 decimal places)
2g Cl = 2/35.5 = 0.0563 moles of chlorine atoms but 3 needed per molecule of AlCl3
so 0.0563/3 = 0.0188 (4 decimal places) maximum number of moles of product possible.
0.0188 x 133.5 = 2.51 g maximum yield.
Wiki User
∙ 12y ago
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