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1 1/2 cup kidney beans

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500ml of 30% solution

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Q: How do you determine the number of grams of an active ingredient in a solution based on the percent strength?
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Determine the strength of a polymer solution as a percent if 80 grams of polymer are mixed with 16 liters of water?

0.1125% of polymer solution.


Percents are often used to show the strength of solutions Which solution is stronger the 2 percent or the 3 percent?

A 3 percent solution is 1.5 times as strong as a 2 percent solution.


To figure out the exact pH of a solution you'll need to determine the?

You need to determine the percent of hydrogen (pH) molecules in the solution.


Is 1 percent solution equal to 1 normal solution?

No - 1% solution is 1/100th the strength of the original.


What determine the strength of acid?

For normal acids, pH is most accurate. For hydrofluoric acid, pH is NOT a good indicator--a 1-percent HF solution has a lower pH than a 50-percent solution does, and a 10-percent HF solution has the highest pH of all. The range is from 3.1 (for a 1-percent solution) to 4.5 (for a 10-percent solution). HF is considered a weak acid--not all the HF molecules dissociate when the HF gas is put into water--but it's the most corrosive acid around.


How much active ingredient would you weight to make 100ml of a 50 percent solution?

50 g


How many grams of active ingredient will you need to prepare 2.5 gallons of a 45.6 percent solution?

4314.9 grams


How many grams in 1 percent solution?

A 1% solution normally contains 1 gram of active ingredient per 100 ml of solution (weight-volume percent) Could also be 1gm per 100 gms (weight-weight percent)- but normally weight-volume is used.


1g of a drug is dissolved in 2.5mL of solution what is the percentage strength of the solution ww How do you calculate percent ww when 1g of drug is dissolved in 2.5mL of solution?

40%


How many ml of active ingredient are in 1.5 liter of a 17.5 percent solution?

1.5L = 1500ml17.5 X 1500 / 100 =262.5ml


How many liters of a 40 percent acid solution must be added to 100 liters of a 25 percent solution to obtain a 30 percent solution?

Suppose L litres are required.@ 40% it will contain 0.4L of the active ingredient.Then total volume of mixture = L + 100 litresand volume of active ingredient = 0.4L + 25 litresThe strength is (0.4L + 25)/(L + 100) = 30% = 0.3(0.4L + 25) = 0.3*(L + 100)0.4L + 25 = 0.3*L + 300.1L = 5L = 50 litres.


How much of a 50 percent solution should be added to 1 liter to make a 25 percent solution?

Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.