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Answered 2013-08-25 02:07:51

Subtract two times the length from the perimeter and cut that answer in half.

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multiply the width by 2 and then subtract that to the perimeter then divide the answer by 2 to get the length


Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.


perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in



If you are given the width and the perimeter, then figure out what the length is then calculate the area... hope this helps :)


The width would be: P - (L*2) = W*2 Perimeter = P Length = L Width = W


you have to add all of the outside to get the perimeter of the answer.


Subtract two times the length from the perimeter and divide the remainder by two. This should be the width.


All we can tell from the information you have given is that the length plus the width is 8.8...


If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length



perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length


It not possible you nit witt that is not true length x width = area If you know length and area, solve width width = area / length then 2 x length + 2 x width = perimeter


Given the available information, the length and width are indeterminate.


Length + length + width + width = perimeter. Length + width x 2 = perimeter


Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.


Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .



By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.


Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length


If you double its length and double its width and add those two amounts together you have the perimeter.


The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.


Assuming you mean a rectangle: use the formula:p = 2(l+w) (i.e., perimeter equals twice length plus width). In this formula, replace p with the known perimeter, and l with the given length, then solve for width.


First of all, the area cannot be 40 cm since an area is 2-dimensional whereas the measure given is 1-dimensional. Next, the shape is not defined and so the width, length and perimeter are indeterminate. Even if you assume that the shape is a rectangle, the width, length and perimeter are indeterminate. On the basis that the length is greater than the width, all that you can say is that the length will be greater than or equal to sqrt(40) = 6.324555 (to 6 dp), the width will be 40 divided by that length and the perimeter will be twice their sum. Some examples: Length = 8, width = 5, perimeter = 26 Length = 10, width = 4, perimeter = 28 Length = 40, width = 1, perimeter = 82 Length = 4000, width = 0.01, perimeter = 8000.02 Length = 4,000,000, width = 0.00001, perimeter = 8,000,000.00002 and so on, without limit.




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