your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i

16y2-8y=0 8y(2y-1)=0

0 squared is 0. Zero times zero equals zero.

If you mean: x2+9x+20 then it is (x+4)(x+5) = 0 when factored

Since 3 squared is 9 and 9 - 9 equals 0, that's going to be tough to factor.3x2 - 9 factors to 3(x2 - 3)

x2 - 5x = 0Factor the left side:x (x - 5) = 0x = 0x = 5

It equals 0. Zero times zero equals zero.

It can not be factored because its discriminant is less than zero

Solve this problem -x squared -40x- 80 =0

x2-11x = -10 x2-11x+10 = 0 (x-1)(x-10) = 0

It can be simplified in the form of: 2x3+9x2-7x-34 = 0

If x squared -10 = 0 then x = the square root of 10

0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18

4+4+4and 6+6+0 and 2x3+6

5x2 - 6x = 0Factor the left side:x (5x - 6) = 0The equation is satisfied ifx = 0,or if5x - 6 = 05x = 6x = 6/5

True because in both equations x = 0 or x = -4

No, it equals 0. If you have nothing, and you multiply it by nothing, you still have nothing.

3X = x2 - 2xsubtract 3X from each sideX2 - 5X = 0factor out an XX(X - 5) = 0=========X = 0--------orX = 5--------

x2 + 6x = 0 The only factor common to both terms is 'x'. x(x + 6) = 0 To solve this equation then one or both of the factors must equal zero. Then x = 0, or x + 6 = 0 which occurs when x = -6.

x2-2x-10-5 = 0 x2-2x-15 = 0 (x+3)(x-5) = 0 x = -3 or x = 5

If: n squared = 10n+56 Then: n squared -10n -56 = 0 When factored: (n-14)(n+4) = 0

2x 2 + 5x – 7 = 0

If x2 is zero, then x=0 (and no, that is not an emoticon) The only root of zero is zero.

(x, y) = (-3, -3) or (3, 3)

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