Math and Arithmetic

Trigonometry

Top Answer

Depending on your calculator, you should have an arcsin function, which appears as sin^-1. It's usually a 2nd function of the sin key. If you don't have this function, there are many free calculators you can download... just Google scientific calculator downloads.

Anyway, this inverse function will give you theta when you plug in the value of sin theta. Here's the algebra written out:

sin(theta)=-0.0138

arcsin(sin(theta))=arcsin(-0.0138)

theta=.......

The inverse function applied to both sides of the equation "cancels out" the sin function and yields the value of the angle that was originally plugged into the function, in this case theta. You can use this principle to solve for theta for any of the other trig functions:

arccos(cos(theta))=theta

arctan(tan(theta))=theta

and so on, but calculators usually only have these three inverse functions, so if you encounter a problem using sec, csc, or cot, you need to rewrite it as cos, sin, or tan.

sec=1/cos

csc=1/sin

cot=1/tan

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0theta = arcsin(0.0138) is the principal value.

If sin(theta) is 0.9, then theta is about 64 degrees or about 116 degrees.

Theta equals 0 or pi.

sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o

2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))

If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.

sin(0)=0 and sin(very large number) is approximately equal to that same very large number.

2 sin (Î˜) + 1 = 0sin (Î˜) = -1/2Î˜ = 210Â°Î˜ = 330Â°

when sin theta almost equals to theta in radians

If sin2(theta) = 0, then theta is N pi, N being any integer

It will be a circle.

you have to do the arcsin which is sin-1 on your calculator. i have not met anyone in my life who can do sin or arcsin in their head. not even my college teachers. your theta is equal to 20degrees

It's 1/2 of sin(2 theta) .

The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))

Yes, it can. If you plot theta and sin(theta) on the same graph, you will see where they intersect. I do not know of an analytical expression for this point; I think only numerical results are possible.

For such simplifications, it is usually convenient to convert any trigonometric function that is not sine or cosine, into sine or cosine. In this case, you have: sin theta / sec theta = sin theta / (1/cos theta) = sin theta cos theta.

It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!

(Sin theta + cos theta)^n= sin n theta + cos n theta

2 sin(x) + 1 = 0 2 sin(x) = -1 sin(x) = -1/2 x = 210Â° and 330Â°

The only real solution is theta = 0For theta For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.The only real solution is theta = 0For theta For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.The only real solution is theta = 0For theta For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.The only real solution is theta = 0For theta For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.

Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).

Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.

(/) = theta sin 2(/) = 2sin(/)cos(/)

Sin theta of 30 degrees is1/2

It is not! So the question is irrelevant.

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