a = (v2 - u2)/2s
where
a is the acceleration between the initial point in time and the final point in time,
u is the initial velocity
v is the final velocity
s is the distance travelled
The distance travelled by an object in a given time is given by:Distance = Speed * TimeAlternatively for an object that is accelerating:Distance = (Speed of object before acceleration is applied * Time) + (0.5 * Acceleration * Time squared)If the object is accelerating from speed zero, the first set of brackets is irrelevant.Also, if the object is falling to the ground, acceleration = 9.81
Speed = distance / time.
work = force * distance and force = mass * acceleration and acceleration = change in velosity/change in time so work = mass * acceleration * distance , as a result work = mass * change in velosity/change in time * distance, hence the velocity of the object affected by : 1.mass of the object. 2. gravitational acceleration which reduces the speed of the object when go up and increases the speed of the object when it come down.. 3. look at the rules etc........thx..............with best regards
acceleration times speed
Speed = (distance covered) divided by (time to cover the distance) Speed = (magnitude of acceleration) multiplied by (time the acceleration has acted)
The distance travelled by an object in a given time is given by:Distance = Speed * TimeAlternatively for an object that is accelerating:Distance = (Speed of object before acceleration is applied * Time) + (0.5 * Acceleration * Time squared)If the object is accelerating from speed zero, the first set of brackets is irrelevant.Also, if the object is falling to the ground, acceleration = 9.81
Speed = distance / time.
Its acceleration due to gravity is constant. The acceleration is equal to the object's change in speed every second. I've tried to illustrate the constantly-increasing falling speed in my diagram below.
neither speed nor acceleration
As a falling object accelerates through air, its speed increases and air resistance increases. While gravity pulls the object down, we find that air resistance is trying to limit the object's speed. Air resistance reduces the acceleration of a falling object. It would accelerate faster if it was falling in a vacuum.
No, that won't do it. You need to divide the distance the object went by the time it took to go that distance.
No. It's the rate at which a object changes velocity (speed).
the constant speed that a freely falling object eventually reaches when the resistance of the medium through which it is falling prevents further acceleration.
The speed stays thesame but the distance stays the same.
If an object is in motion, we apply the term speed to the distance (displacement) it achieves for a given unit of time. If we take speed and add a direction vector, as is asked here, we are talking about the velocity of the object.
The bigger the object the faster it causes it to fall until it reaches terminal velocity, then it falls at a constant speed.
If the object is falling in vacuum, then its direction is downward, and its speed at any time is Speed = (speed when time started) + [(acceleration of gravity) x (number of seconds since time started)]. If the object is falling through air, water, or some other fluid, then the formula is much, much more complicated. It involves the object's mass and shape, and the properties of the fluid it's falling in.