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The change in solution volume will be the volume of the sphere. Let's call that V We know that the volume of a sphere is 4/3 Pi x r^3 So the cube root of 3v/4Pi is the radius, double it and you have the diameter. OR Volume of sphere is 1/6 Pixd^3 so 6V/Pi is the diameter cubed. Take the cube root of 6V/Pi and that is the diameter.

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Q: How do you find the diameter of a sphere in solution when change in solution volume after addition of sphere is given?
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