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How do you find the point of intercept of two equation without graphing it?
Wiki User
∙ 13y ago
The two equations must involve 2 unknowns. If there is only 1 unknown, the 2 equations must be the same (or one a simple multiple of the other). Using one of the equations, turn it into a form where one of the unknowns is expressed in terms of the rest of the equation. Then use this expression to substitute for that unknown in the other equation. This other equation now involves only one unknown so you can simplify it to find its value. Use that value in either of the original equations to find the other value.
Example 2x + 3y =8 and x-y=-1. From the 2nd equation you have x=y-1 and use that in the 1st equation to get 2(y-1)+3y=8, which depends only on y. Simplify to get 2y-2+3y=8, so 5y=10 and y is 2. Use that in either of the 1st pair of equations to get 2x+6=8 (or from the other equation x-2=-1) Either way, x=1.
Wiki User
∙ 13y ago
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How do you find the equation of a line without graphing?
There are a couple ways to determine the equation of a line without graphing. How to proceed depends on what you know about the line. Do you know a point, (x1, y1), and slope, m? Then use the point-slope formula, Do you know two points on the line, say (x1, y1) and (x2, y2)? Then use the two-point formula,
How you can solve equations with graphing?
An equation to be graphed must be written (or must be entered in a graphing calculator) in the form y = ..., that is, y must be expressed as a function of x. After a graph is displayed in your graphing calculator, you can use the calculator's TRACE feature to find the x-intercept(s) (a point that the graph intersects the x-axis where y = 0). Move the TRACE cursor to a point just below the x-axis and press ENTER, MOVE the TRACE cursor to a point just above the x-axis and press ENTER, press ENTER again. In this way you can find the x-intercept(s). Thus, each x-intercept of the function is a real solution of the equation to any desired degree of accuracy.
What does the y-intercept of a line mean?
At what point the line intersects the y-intercept, in an equation y=mx+b, b is the y-intercept.
What is the y-intercept of this equation y equals 2x plus 5?
The y-intercept is the point where the line hits the y-axis when graphed. In order for a point to be on the y-axis, the x-value must equal zero. Therefore, substitute zero for "x" in the equation to find the y-intercept. y-intercept = (2)(0) + 5 y-intercept = 5
How do you write an equation of a line given the y-intercept and a point?
y=mx+b, right? So, b is the height of the y-intercept that you already have. M is the slope, rise over run. The slope is the same at all part of a line. You take the distance up from the y-intercept to the point and divide by the distance right from the y-intercept to the point. Replace m with that and you have the equation.
How do you find the equation of a line without graphing?
There are a couple ways to determine the equation of a line without graphing. How to proceed depends on what you know about the line. Do you know a point, (x1, y1), and slope, m? Then use the point-slope formula, Do you know two points on the line, say (x1, y1) and (x2, y2)? Then use the two-point formula,
What is the y-intercept of a linear equation?
The y-intercept of a linear equation is the point where the graph of the line represented by that equation crosses the y-axis.
How you can solve equations with graphing?
An equation to be graphed must be written (or must be entered in a graphing calculator) in the form y = ..., that is, y must be expressed as a function of x. After a graph is displayed in your graphing calculator, you can use the calculator's TRACE feature to find the x-intercept(s) (a point that the graph intersects the x-axis where y = 0). Move the TRACE cursor to a point just below the x-axis and press ENTER, MOVE the TRACE cursor to a point just above the x-axis and press ENTER, press ENTER again. In this way you can find the x-intercept(s). Thus, each x-intercept of the function is a real solution of the equation to any desired degree of accuracy.
Is the point slope equation the same as the point slope intercept form?
no it is different
What is slope y-intercept of y -7x 3?
To figure out the slope and y-intercept of y-7x=3, rearrange the equation in to slope-intercept form, or y=mx+b. Y-7x=3 rearranged is y=7x+3. The slope is the coefficient with x, so here it's 7, or 7/1. This means for every seven units the lines goes up, it goes to the right once. To figure out the y-intercept (the point where the line crosses the y-axis) punch the equation into a graphing calculator or graph it manually. In this equation, the y-intercept is (-1/2, 0).
Can you write the equation of a line with one point on the line?
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
What does the y-intercept of a line mean?
At what point the line intersects the y-intercept, in an equation y=mx+b, b is the y-intercept.
How do you graph 3x plus 4y equals -4?
3x+4y=-4 can be graphed on a graphing calculator or by changing the form of the equation from standard form to slope intercept form. Rearrange the equation 4y=-3x-4 divide by 4 y=(-3/4)x-1 Now, you can simply graph the equation using the y intercept and the slope of the equation. A good point to start with is (0,-1) you know this point is the y intercept because of the standard y intercept equation y= mx+b where b is the y intercept and m is the slope. From the y intercept of (0,-1) you can then graph using the slope which is the change of y over change in x. So you would move up 3 and to the left 4 since the slope is negative. You can also move down three and to the right 4. Then continue, this process until you have the equation graphed. It should be a straight line.
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 1 1?
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
What is the y intercept of the equation 5x-2y equals 10?
The point (0, -5) is the y-intercept (x = 0)
What is the point at in which a graph intersects the y-axis.?
It is called the y-intercept and is the constant term in the relevant equation.
What are the 3 cases that might arise when graphing a linear and quadratic function on same grid?
They intercept at:no pointsone point onlytwo points.
