At the point of intersecting lines, the points are equal.
The equation of the 1st line is Y=3x-7
The equation of the 2nd line is Y=-2x+3
Remember, at the intersecting points they are equal. So then:
3x-7=-2x+3 Now solve for x (get x by itself in the form of x=whatever)
+2x +2x (What you do to one side of the equal sign you must do to the other)
5x -7 = 3
+7 = +7
5x = 10 now divide by 5 to remove the 5 from the x in 5x.
Then you sub x=2 into any of the two equation. Lets use the first one:
Y=3x-7 becomes Y=3(2)-7
So the intersecting point is (2,-1)
Solve the two equations simultaneously. The solution will be the coordinates of the point of intersection.
It would help to know "... the point of intersection of a parallelogram" and what!
Graph the two lines or equations you want to find the intersection of. Then adjust the window so that you can see the intersection point. (If you don't know where it is, try pressing ZOOM and choosing ZoomFit.) Then press 2ND CALC (above TRACE) and choose option 5, intersect. Use the up and down arrows to select the first equation you want to find the intersection point on, and press ENTER. Do the same thing for the second equation. The calculator will now say "Guess?". Use the left and right arrows to move the x-like shape as close to the intersection point as possible, then press ENTER. The calculator will tell you the intersection point and the bottom of the screen. If you get a NO SIGN CHNG error, then it might be because the intersection point is not on the screen. Change the window so that you can see the intersection point and try again. Also, make sure that your guess is somewhat close to the intersection point.
Unless the line is a subset of the plane, the intersection is a point.
There is a difference between where the two lines meet and where the greatest tempurature change is... think about it... the two lines do not meet where the greatest tempurature change is, the two lines meet where the greatest amount of heat is given off...
graphing method is when you graph two lines and then find the intersection which is the answer of the system of equations
You must first write an equation for the line through the point perpendicular to the line. Then, find the intersection between the two lines. Lastly, use this point and the distance formula to find the length of the perpendicular segment connecting the given point and the original line. That will lead to the following formula, d = |AX1+BY1- C|/(sqrt(A2+B2)), Where A, B and C represent the coefficients of the given line in standard form and (X1,Y1) is the given point.
Yes, an Octagon does have a center point. The easiest way for me to find this is by drawing lines between opposite vertexes. You should end up with four lines and they should be crossing at one point. That is your center point! :V
when the x and y values of both equations are equal, because the point of intersection will only have one x value and one y value
The step to verify an isosceles triangle is: 1) Find the intersection points of the lines. 2) Find the distance for each intersection points. 3) If 2 of the distance are the same then it is an isosceles triangle.
Assume the room to be square or rectangle. The intersection of two lines from opposite corners is your center.
The difference between interior lines and exterior lines are thatInterior lines: Are the lines that are in the inside of the shape or whatever you are trying to find the interior of.Exterior Lines: Are the lines that are outside of the shape or whatever you are trying to find the exterior of.
Grid references are points defined by the coordinates of a grid or map system. The reference numbers can be used to denote a particular point or area on the grid. Most maps are labeled with numbers or letters on horizontal and vertical lines to allow you to find a given point (the intersection of those lines). Geographic maps may use latitude and longitude.
If the distance between the lines is constant then they are parallel.
It shows us the intersection of the lines of latitude and longitude, which measure north-south and east-west respectively. In this way, we can identify the location by finding the intersection points.
x + y = 6x + y = 2These two equations have no common point (solution).If we graph both equations, we'll find that each one is a straight line.The lines are parallel, and have no intersection point.
A right angle is the angle between two perpendicular lines, and, as such, has no area. You could make a right triangle from such an intersection of lines, but you need more info before you can find the area. A right angle is measured as 90 degrees or π/2 radians.
intersection of the lines drawn perpendicular to each side of the triangle through its midpoint
If the two lines are parallel, then the shortest distance between them is a single, fixed quantity. It is the distance between any point on one line along the perpendicular to the line.Now consider the situation where the two lines meet at a point X, at an angle 2y degrees. Suppose you wish to find points on the lines such that the shortest distance between them is 2d units. [The reason for using multiples of 2 is that it avoids fractions].The points are at a distance d*cos(y) from X, along each of the two lines.
where the two lines cross is called their point of intersectionHere we will cover a method for finding the point of intersection for two linear functions. That is, we will find the (x, y) coordinate pair for the point were two lines cross.Our example will use these two functions:f(x) = 2x + 3g(x) = -0.5x + 7We will call the first one Line 1, and the second Line 2. Since we will be graphing these functions on the x, y coordinate axes, we can express the lines this way:y = 2x + 3y = -0.5x + 7Those two lines look this way:Now, where the two lines cross is called their point of intersection. Certainly this point has (x, y) coordinates. It is the same point for Line 1 and for Line 2. So, at the point of intersection the (x, y) coordinates for Line 1 equal the (x, y) coordinates for Line 2.Since at the point of intersection the two y-coordinates are equal, (we'll get to the x-coordinates in a moment), let's set the y-coordinate from Line 1 equal to the y-coordinate from Line 2.The y-coordinate for Line 1 is calculated this way:y = 2x + 3The y-coordinate for Line 2 is calculated this way:y = -0.5x + 7Setting the two y-coordinates equal looks like this:2x + 3 = -0.5x + 7Now, we do some algebra to find the x-coordinate at the point of intersection: 2x + 3 = -0.5x + 7We start here.2.5x + 3 = 7Add 0.5x to each side.2.5x = 4Subtract 3 from each side.x = 4/2.5Divide each side by 2.5.x = 1.6Divide 4 by 2.5.So, we have the x-coordinate for the point of intersection. It's x = 1.6. Now, let's find the y-coordinate. The y-coordinate can be found by placing the x-coordinate, 1.6, into either of the equations for the lines and solving for y. We will first use the equation for Line 1:y = 2x + 3y =2(1.6) + 3y = 3.2 + 3y = 6.2Therefore, the y-coordinate is 6.2. To make sure our calculations are correct, and also to demonstrate a point, we should get the same y-coordinate if we use the equation for Line 2. Let's try that:y = -0.5x + 7y = -0.5(1.6) + 7y = -0.8 + 7y = 6.2Well, looks like everything has worked out. The point of intersection for these two lines is (1.6, 6.2). If you look back at the graph, this certainly makes sense:Here's the summary of our methods:Get the two equations for the lines into slope-intercept form. That is, have them in this form: y = mx + b.Set the two equations for y equal to each other.Solve for x. This will be the x-coordinate for the point of intersection.Use this x-coordinate and plug it into either of the original equations for the lines and solve for y. This will be the y-coordinate of the point of intersection.As a check for your work plug the x-coordinate into the other equation and you should get the same y-coordinate.You now have the x-coordinate and y-coordinate for the point of intersection.Actually, there is nothing special about the functions being linear functions. This method could be used to find the point or points of intersection between many other types of functions. One would express the functions in 'y =' form, set the right side of these forms equal to each other, solve for x, (or x's), and use this x, (or x's), to find the corresponding y, (or y's).Here's a calculator to help you check your work. Make up two linear functions in slope-intercept form. Calculate the point of intersection using the above methods. Then enter the slope and y-intercept for each line into the calculator and click the button to check your work.
Join any pointof the image(a vertex is ideal) to the corresponding point of the pre-image by a straight line. Repeat for another point. These two lines will intersect at the centre of enlargement. As a check, repeat for a third pair of points: if the third line does not go through the point of intersection of the first two, you have made a mistake.