Math and Arithmetic

How do you find the width to length ratio of each rectangle?


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2012-02-21 04:56:45
2012-02-21 04:56:45

Divide the width by the length:




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You really can't unless you know something else about the length or width or even the area of the rectangle. You have 2 unknowns (length & width) & only one equation (perimeter). In order to find 2 unknowns you need 2 equations, that's why you need to know something else about the rectangle such as how the length & width are related to each or the area of the rectangle. Hope that helps.

Each face of a box is a rectangle . The area of a rectangle is (its length) times (its width). Measure the length and width of each face, and multiply (length times width). If you think about what you're doing, and plan it carefully, you only have to make three measurements and you'll have the whole box covered ... all six faces.

It depends on what information you do have. The length and area, the length and diagonal, the length and perimeter, etc. Each set generates a different answer.

For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.

A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.

Perimeter is the length of a closed line around an area. A rectangle is an area. If each long side of the rectangle is 12 cm and each end of the rectangle is 9 cm, the total length is 14+14+9+9 or 46 cm.

All we can tell is length plus width is 606.5 ...(always assuming you're talking about a rectangle)

1.10*X=402. Divide each side by 10:X=4 centimeters3. Check your answer 10*4=40The width of the rectangle is 4 centimeters

Multiply by length x the width of the room. Sometimes the room is not just a rectangle. Then you must divide it up into smaller pieces each of which is a rectangle.

No you add the sides of the shape together such as a square which is 2 in on each side. So you add 2+2+2+2 or 2x4. The answer to area is length times width.

You multiply its length and its width by 2.5

The area of a square is calculated the same as that of a rectangle: length x width.

First we have to find out what 'x' is. Then we'll know the length and width,and we can multiply them to find the area.Length of the rectangle = x - 2Width of the rectangle = 2xPerimeter of the rectangle = (two lengths) + (two widths) = 2(x-2) + 2(2x) = 2x - 4 + 4x = 6x - 4.But we know that the perimeter is 452.So (6x - 4) = 452Add 4 to each side:6x = 456Divide each side by 6:x = 76.Now we know what 'x' is.Length = x - 2 = 74Width = 2x = 152Area = (Length) x (Width) = (74 x 152) = 11,248===========================The answer is 11,248.Nice work. I'll bet you learned a lot from having me do it.

Rectangles don't have height. They have length and width, one value for each. The area is the product of those two values.

There is insufficient information to provide a unique answer. Assuming that the length is greater than the width, the length, L, can be any measure from 5 to just under 10 units. The width would then be 10-L units.

Divide the room into two rectangles. Then calculate the area of each rectangle as length x width.

Yes of course. Each rectangle will have a width half its length.

If the lawn is rectangular (or square) then measure its length and width - in feet. The area is length * width. If it is odd shaped, try and mark out rectangles, measure their area as above and then add together the answers for each rectangle.

It is the same as the area of a rectangle, you simply x length by width. This is because the slanted edges kind of cancel each other out.

The width is 34 feet. Since you know the length (l) of one side is 1 foot, and the perimeter is 70 feet, then each of the longest sides is 70/2-l

Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.

Perimeter = 2w + 4w = 6w=60 w=10 The answer is 10 cm. w is the width, 2w is the length and there are two of each kind of side, hence 2(w) + 2(2w) = 6w

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