The period of the earth's orbit around the sun is one year. The period of earth's orbit about its own axis is one day. If we estimate one year to be about 365 days, we simply get the ratio 365:1 as the ratio of the period of earth's orbit around the sun to that of earth's rotation about its own axis.
Orbital period = 365 days
Rotation period = 1 day
Ratio 365:1
Inner planet
IT IS not The same Period of rotation Because tthe mercury have rotation g9 days and the pluto have a rotation 6.4 days so it is not the same BY:JULLIA TUTANES :P
In the time it takes Mercury to complete one rotation, Neptune rotates 87.37 times.
The answer will depend on ratio of which characteristic. Each of the following will have a different ratio:radius, surface area, volume, mass, density, surface gravity, average distance from the Sun, perihelion, aphelion, orbital period, orbital eccentricity, rotational period, atmospheric pressure, albedo. And there are many more besides. Without some focus, this question is a complete waste of time.
Gravity behaves exactly the same on Mercury as it does everywhere else in the universe. Taking into consideration the mass and radius of Mercury, you would calculate that the the acceleration due to gravity at its surface, and therefore the weight of any object on its surface, are about 38% of what they are on Earth, and you'd be correct. That's what they are.
Inner planet
IT IS not The same Period of rotation Because tthe mercury have rotation g9 days and the pluto have a rotation 6.4 days so it is not the same BY:JULLIA TUTANES :P
In the time it takes Mercury to complete one rotation, Neptune rotates 87.37 times.
In the time it takes Mercury to complete one rotation, Neptune rotates 87.37 times.
The answer will depend on ratio of which characteristic. Each of the following will have a different ratio:radius, surface area, volume, mass, density, surface gravity, average distance from the Sun, perihelion, aphelion, orbital period, orbital eccentricity, rotational period, atmospheric pressure, albedo. And there are many more besides. Without some focus, this question is a complete waste of time.
There are about 63 known moons of Jupiter but the Galilean moons are the 4 moons visible and Ganymede ,the largest found by Galileo Galilee in January 7 1610.The orbital speed of the Jovian moons vary where the Jupiter's magnetic field is very strong.Only a mean speed can be used for comparison.The four moons and their orbital speed compared to the orbital speed of Earth's moon are:Jovian Moons Orbital speed/ Orbital speed Ratio(km/s) (Earth's moon)1. Io orbital speed 2.75 km/sEarth's moon orbital speed 1.03 km/s Ratio 1: 2.672.Europa orbital speed 2.187 km/sEarth's moon orbital speed 1.03 km/s Ratio !: 2.123. Callisto orbital speed 1.732 km/sEarth's moon orbital speed 1.03 km/s Ratio 1: 1.684.Ganymede orbital speed 1.305 km/sEarth moon's orbital speed. 1.03 km/s Ratio 1: 1.27
For the purposes of this question we will consider a planet as a solid body - which it pretty much is anyways. As a result of a planet's formation it is left with some rotational energy. This is merely a result of chaotic systems and it would be extremely difficult to have a body with exactly zero rotational energy. Since the planet is a solid body it has to turn uniformly- an as it turns uniformly there has to be an axis of rotation, a line through the body around which it turns. If a planet is a long ways away from it centre of orbit the tidal forces are negligable and there is no impediment to it rotation. All the planets Earth and beyond rotate with a period different from their period of orbit. Venus and Mercury are tidally locked with their solar orbital period in some resonance ratio. Earth's moon and most planetary moons are like-wise tidally locked with a period similar to their orbital period. It has been proposed that Uranus was hit by some massive object that alterned its axis of rotation to an extreme degree. If this is true the mass and energy of the object must have been considerable.
Gravity behaves exactly the same on Mercury as it does everywhere else in the universe. Taking into consideration the mass and radius of Mercury, you would calculate that the the acceleration due to gravity at its surface, and therefore the weight of any object on its surface, are about 38% of what they are on Earth, and you'd be correct. That's what they are.
i have no clue rawr
Rotation, no. Lift, yes. If you increase the surface area of the propeller, then you alter the lift to weight ratio.
Johannes Kepler, working with the detailed observational data compiled by Tycho Brahe, showed that the ratio of (orbital period)2 to (mean distance from the sun)3 is a constant for the earth and the five other visible planets. A generation after Kepler, Sir Isaac Newton showed that his law of universal gravitation could predict the shape and periods of the planetary orbits.
The farther a planet is from the sun, the longer it takes to revolve around the sun in its orbit. The ratio of (Orbital period)2/(Semi-major axis)3 is a constant for every object in solar orbit. (That's Kepler's 3rd law of planetary motion.)