Y = 2X + 3
The graph is a straight line, with a slope of 2, passing through the point Y=3 on the Y-axis.
-- From the point Y=3 on the Y-axis, move 1 to the right and 2 up. This brings you to the point (1, 5). Mark the point.
-- Place your ruler so that the point Y=3 and the point (1, 5) are both along the edge. Draw the line.
First, you must solve for y.
So, the problem begins as 2x+y=3 so to solve for y, you subtract 2x from both sides so this results in y= -2x + 3 (remember what you do to one side you must also do to another) so from there you may graph this by beginning at the origin and shifting up 3 spots on the y-axis, (this is your y intercept) for this equation b =3. Then you look at your slope which is (-2/1) which means you rise -2 (which means do down two from your y-intercept) and the run 1 (to the right)
-2x+y=-3 add 2x to the other side y=-3+2x on the graph you then go down -3 and to the right 2
-2x is the slope and 3 is the y-intercept so you start at (0, 3) and go down -2 and over 1.
2,4
2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3
A graph that has 1 parabolla that has a minimum and 1 positive line.
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
y=-10x-4
The x-interceptin is where the graph crosses the y-axis, which is where y equals 0: 0 = 2x + 3 2x = -3 x = -3/2 So the x intercept is as x = -3/2 (and y = 0).
x^3=2x+5 x^3-2x-5=0 Graph the equation or use a calculator. x= 2.09455148
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
(2x + 3)(2x + 3)
4x + 3 = -3 + 2x + 14 2x + 3 = -3 +14 2x + 3 = 11 2x = 8 x=4
2x = x+3 2x-x = 3 x = 3