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Answered 2012-04-29 14:00:57
As long as you are able to repeat numbers, one way of doing so is by saying:
3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 + 3 + 7 = 1480
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which numbers are divisible by 3? 185 333 111 555 222 74 888 2664 1480 740 148 296
There are only two numbers that can be multiplied to make 15. These numbers are 3 and 5. This is true because 3*5 = 15
1480 grams = 3 pounds 4.21 ounces
if your using whole numbers, u can only use 3
What numbers are only divisible by 2 and 3 .
225 cannot be factorised into the product of only 3 prime numbers.
If the only operation is addition, then 3.
3 + 3 + 3 + 3 + 2 +2 + 1 = 17
I might be reading this incorrectly, but it seems to me that I can take two prime numbers, 3 and 3, and make the square number nine out of them. This is also true of all the other prime numbers.
two that make 39 their difference is 11
1 and 3. These are the only whole numbers to go into both 27 and 30.
Using only sums and differences, and not necessarily all four numbers, 1, 3, 9 and 27 will make all numbers from 0 to 40.
The only 3 you could possibly have is 32 1/3, 33 1/3, 34 1/3.
4+2=6 6-3=3 3-1 2
The answer depends on what the numbers have more of when 3 factors!
they are called numbers with 3 factors
0 you can only have 3 layers since you have only 3 numbers so without repeating you would only have 3 layers
2 and 3 are the only consecutive integers that are prime numbers.
2, 3 and 13 are the only prime numbers that combine to make 78.
It can be: 2*3+4+1 = 11
333, 111, 555, 222, 888, 2664
3 is divisible by only 1 and 3.
2 and 5 are the only prime numbers which differ by 3.
If you want 4-digit numbers, there are 24 of them.
3 and 1, as well as -3 and -1, are the only numbers that, when multiplied, produce a product of 3.
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