5 millimolar (5 thousandths of a mole per liter) is equal to 5000 micromolar ( 5000 millionths of a mole per liter). To make a 50 micromolar solution from 5 millimolar stock solution, you therefore need 5000/50 = 100 fold dilution.
Remove a 10 ml aliquot of stock and transfer to a 1000ml (1 liter) volumetric flask. Dilute with the solvent -usually water, and fill up to the graduation mark. You will now have 1 liter (1000 ml) of 50 micromolar solution.
- Divide the molar mass of the compound with 1 000 000.
- Multiply with 200.
- Weigh this mass if it is possible; alternatively obtain this mass from a stock solution.
- Dissolve this compound in 1 L of demineralized water.
Dissolve 2ml from stock in 8ml of diluent.
take 1ml from stock solution and dilute to 10ml of water to get 10 micromolar solution
dilute it twofold. this means if you choose a 100ml volumetric, take 50ml of your stock and fill it to the mark (another 50ml) with solvent
Any dilution of 100,000 (= 1,000,000 / 10) will do, eg. 1 mL added up to 100 L.
The easiest way would be to take a 25 ml aliquot of the 50 micromolar solution with a pipette and transfer to a 50 ml volumetric flask and then make up to the mark with distilled water.
combine 100 mL 6 M HCl with 500 mL H2O
RMM of CuSo4 . 5H2O = 160 + 5x18 = 250 g How much contain gram in 100 mL of 0.050 M CuSO4 solution is - Solution: = 0.050 x 100/1000 x 250 = 0.050x4 (100)/ 16 = 1.25 g
100 mL of solution 1 M mixed with 900 mL distilled water
V1M1 = V2M2(x ml)(2 M) = (100 ml)(0.4 M) x = 20 ml Take 20 ml of 2 M magnesium sulfate solution and dilute to a final volume of 100 mls.
Take 100 grams of 5% solution and do one of the following:Mix 95 g of it with 5 grams of sugar to end up with 100 g of 10% solution, or, when you are short of sugar:Evaporate 50 grams of water from 100 g of the 5% solution to end up with 50 g of 10% solution.
combine 100 mL 6 M HCl with 500 mL H2O
7
triton x-100 stock percent? 100% ?
When you are looking to make a potassium thicyanate solution you have to dissolve 0.972 g of KSCN in enough H2O to make a 100 mL solution.
Preparation of standards Prepare a stock uric acid solution of 100 mg/L. Dilute it to give working concentrations of 10, 20, 30, 40, 50 and 60 mg/L. Procedure:1 Prepare a 100 mg/L stock solution of uric acid Weigh out 100 mg uric acid, transfer it to a 1 L volumetric flash, add about 900 ml distilled water, and then add about 100 µl of 0.6 N NaOH to help dissolve the uric acid. Make up to the volume with water when uric acid is fully dissolved.2 Dilute the stock solution to give working concentrations of 10, 20, 30, 40, 50, 60 mg/L. To prepare 50 ml of the working standards 5, 10, 20, 30, 40, 50 mg/L respectively, weigh 10, 15, 20, 25, 30 g of stock solution into 50 ml volumetric flasks and make up to volume with distilled water.
just took 0.1g phenolphathlein in 50ml of ethyl alcohol and make the solution up to 100 ml
RMM of CuSo4 . 5H2O = 160 + 5x18 = 250 g How much contain gram in 100 mL of 0.050 M CuSO4 solution is - Solution: = 0.050 x 100/1000 x 250 = 0.050x4 (100)/ 16 = 1.25 g
To make a potassium thiocyanate solution, dissolve 0.972 g potassium thiocyanate (KSCN) in enough water to make 100 ml.
If i understand the question correctly, basically you want to make your standard 1/5 the conc of the stock. Therefore, 300ml stock diluted up with solvent
480ml
100 mL of solution 1 M mixed with 900 mL distilled water
100ppm means, you need 100mg in 1oooml. Thus, for 100ml solution, you will need 10mg of methanol to make 100ppm solution.