it depends how many liters or mililiters you want for example:You want to prepare 100mL of 0.1M sodium thiosulfate
first we calculated the grams needed:
100 mL*(0.1 mmole/1 ml)*(248.19 mg/1 mmole)*(1 g/ 1000 mg)
which gives you 2.4819 g of sodium thiosulfate
disolve the 2.4819 grams in 70 mL ofdistilledwater, transfer to a volumetric flask of 100 mL and finish filling it withdistilledwater up to the mark, and then shake to homogenize.
I would dissolve .4g of sodium thiosulfate into 250.0mL of water.
how do you prepare 50mL of 5M sodium acetate buffer from sodium acetate anhydrous (82,03)
how will you prepare 0.38M sodium acetate solution
how to prepare phoshate buffer pH 7.4
The answer is 0,1648 g NaCl.
To prepare a 1,5 M sodium chloride solution we need 87,659 g NaCl.
1.17 grams :)
I'm confused plz answer it
You need 2,92 NaCl.
The way to calculate a primary standard is with an equation. This equation is M^pdt = (N*V*meq^pb)/1000. For example, for K2Cr2O7, the number is 294,187 grams.
Jodate: IO3- + 6e- + 6H+ --> I- + 3H2Oequivalency to:Thio: 6S2O32- --> 3S4O62- + 6e-25.0 ml * 0.106 mmol/ml (KIO3) = 2.65 mmol KIO3 reacting (1:6) with Thio: 6*2.65 = 15.9 mmol sodium thiosulfate. This is in 16.25 ml, so the molarity is 15.9 mmol / 16.25 == 0.978 M thiosulfate
Mix 357 mL acetic acid 0,1 M with 643 mL sodium acetate 0,1 M.
impossible....u want to use a low contrated solution to dilute into a higher contration solution? No way man,...
Dissolve 1,42 g of anhydrous, for analysis sodium sulfate in 1 L demineralized water at 20 oC, in a volumetric flask.
Dissolve 5,8439 g NaCl reagent grade in 1 L demineralized water at 20 0C.
The following table is extracted from the Internet:* For pH=3: mix 982,3 mL 0,1 M acetic acid with 17,7 mL 0,1 M sodium acetate* For pH=4: mix 847,0 mL 0,1 M acetic acid with 153 mL 0,1 M sodium acetate* For pH=5: mix 357 mL 0,1 M acetic acid with 643 mL 0,1 M sodium acetate* For pH=3: mix 52,2 mL 0,1 M acetic acid with 947,8 mL 0,1 M sodium acetate
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