1 part of hydrogen peroxide out of 30% hydrogenperoxide bottle add 10 parts of distilled water
0.666 ml in 999.34 distilled water
Lets say you want an end volume of 500 ml of 3% peroxide. But you dont know how much 30% peroxide to use. Concentration1 X Volume1 = Concentration2 X Volume2 30/100 X unknown ml = 3/100 X 500 ml unknown ml = 50 ml 50ml of 30% added to pure 450 ml of water = 500 ml 3 % peroxide. · 3 years ago
hehehe
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
12 mg
Fractional crystalization of Hydrogen Peroxide would involve lowering the temperature of the solution to just above the melting point. This will depend on the concentration and it is NOT linear. For instance, a 3% solution as is found in most drugstores will freeze at about -2C, 30% at about -25C, 35% at -33C, 50% at -52C, 70% at -40C and finally 90% at about -11C.
0.666 ml in 999.34 distilled water
Lets say you want an end volume of 500 ml of 3% peroxide. But you dont know how much 30% peroxide to use. Concentration1 X Volume1 = Concentration2 X Volume2 30/100 X unknown ml = 3/100 X 500 ml unknown ml = 50 ml 50ml of 30% added to pure 450 ml of water = 500 ml 3 % peroxide. · 3 years ago
by urea hydrogen peroxide reaction with tri fluro acetic anhydride
hehehe
ask your teacher.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
pharmacist
Given that hydrogen peroxide (H2O2) decomposes easily into water and oxygen, H2O9 would probably not be possible to synthesize in real life.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
Too many unknowns in your question. Is this 3% by mass or by volume? Does the quantity of final solution matter? IE do you need 100 ml, 1 liter or 5000ml. What is the density of the hydrogen peroxide? (needed for a volume % problem) Assuming you mean 3% by mass, then that means 3 g of hydrogen peroxide in 100 g of solution. 300 micromolar = 3 x 10-4 molar. Assuming you want to make one liter then you need 3 x 10-4 moles of peroxide. The molar mass of peroxide is 34 g/mole. 34 g/mole x 3 x 10-4 moles = 1.02 x 10-2 grams of peroxide 1.02 x 10-2 grams / .03 = 0.34 grams of the original solution. Weigh (mass) accurately 0.34 g of the original solution in a 1 liter volumetric flask. Add distilled water until the total volume is 1 liter.
The principal uses of the hydrogen peroxide are: - bleaching agent in the paper industry - bleaching agent for textiles - disinfectant /antiseptic - neutralization of hydrogen sulphide - neutralization of nitrogen oxides - treatment of waste waters - treatment of industrial water to delete organic contaminants - starting material to prepare some useful organic and inorganic chemicals - etc.