0
It depends on how much you are trying to make and what you are diluting it from, but the formula for figuring it out is Molarity of starting solution times X (in which X is how much you will be adding) equals Molarity of the solution you are producing times its volume
Wiki User
∙ 12y ago
Wiki User
∙ 8y ago- Add 63,01 g HNO3 to a 1 L volumetric flask.
- Add demineralized water up to the mark at 20 oC
The volume of HNO3 corresponding to 63,03 g must be calculated because depend on the concentration of nitric acid available in laboratory.
Add your answer:
Earn +20 pts
How do you prepare 1 M solution from 6 M solution?
It's simple to dilute a solution, just add more water. If you have one liter of 6 molar solution, and add another 5 liters of water, it becomes a 1 molar solution. You can also use M1V1 = M2V2 formula for dilution. For example, if you want to prepare 1 M of solution in 1 litre of water, then how much volume you need from the initial 6 M solution? Simply use the equation, (6 M) x (V1) = (1 M) x (1 litre) ---> V1 = (1 M) x (1 litre)/(6 M) = 0.167 L or 167 ml
How do you prepare 1 L of 15 M sodium hydroxide solution by diluting the stock solution of 6 M sodium hydroxide?
impossible....u want to use a low contrated solution to dilute into a higher contration solution? No way man,...
How much of a 0.250 M sucrose solution must be used to prepare 400.0 mL of a 0.0310 M solution?
49.6 mL
How to prepare HCL solution?
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
How will you prepare 3 liters of 2.5 M solution of KCl solution in water?
Dissolve 566.25g of KCl in 3L.
How do you prepare M Cal solution?
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
How do you prepare 1 M solution from 6 M solution?
It's simple to dilute a solution, just add more water. If you have one liter of 6 molar solution, and add another 5 liters of water, it becomes a 1 molar solution. You can also use M1V1 = M2V2 formula for dilution. For example, if you want to prepare 1 M of solution in 1 litre of water, then how much volume you need from the initial 6 M solution? Simply use the equation, (6 M) x (V1) = (1 M) x (1 litre) ---> V1 = (1 M) x (1 litre)/(6 M) = 0.167 L or 167 ml
How do you prepare a primary standard solution of 0.0500 M sodium carbonate?
use the equation that is standard: 1000 ml 1 M solution= (MOLECULAR WEIGHT) X ml 0.05 M solution = ((MOLECULAR WEIGHT)*X*0.05)/1000
How do you prepare 10 mm solution with 4 m stock solution?
10-4
How do you prepare 1 L of 15 M sodium hydroxide solution by diluting the stock solution of 6 M sodium hydroxide?
impossible....u want to use a low contrated solution to dilute into a higher contration solution? No way man,...
How much of a 0.250 M sucrose solution must be used to prepare 400.0 mL of a 0.0310 M solution?
49.6 mL
How to prepare HCL solution?
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
Preparation of 0 38 M sodium acetate solution?
how will you prepare 0.38M sodium acetate solution
How will you prepare 3 liters of 2.5 M solution of KCl solution in water?
Dissolve 566.25g of KCl in 3L.
What is the molality of a solution of chlorine and water is 0.0362 m how much chlorine in grams was used to prepare this solution?
8.9g
How many ml of 5 M are required to prepare 1000 ml of 0.02 M NaCl solution what is the dilution factor of this solution?
0.02/5=0.004
How would you prepare a 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water?
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
