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Q: How do you prepare a solution of 1 M H2NO4?

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To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.

To prepare a .1 M solution, the ratio would be .1 moles of HCl per liter of water. This is equal to 3.65 grams HCl.

It's simple to dilute a solution, just add more water. If you have one liter of 6 molar solution, and add another 5 liters of water, it becomes a 1 molar solution. You can also use M1V1 = M2V2 formula for dilution. For example, if you want to prepare 1 M of solution in 1 litre of water, then how much volume you need from the initial 6 M solution? Simply use the equation, (6 M) x (V1) = (1 M) x (1 litre) ---> V1 = (1 M) x (1 litre)/(6 M) = 0.167 L or 167 ml

How to prepare 2M HCl solution from con HCl

Magnesium sulfate is not so soluble in water to prepare a 4 M solution.

Dissolve 74.55g of KCL in some water then volume it up to 1 liter.

10-4

For making 1 MSolution, 40 gm NaoH dissolved in 1000 ml Distilled water .then10 ml solution of 1 M (Stock solution) dissolved in 500 ml distilled water for 0.02 M NaOH solution. R.C Joshi.

10N HCl is equivalent to 10 M HCl and the solution will contain 10 moles of HCl per 1 liter or solution. Depending on the volume of solution, the preparation will vary. To prepare 1 liter, place 360.5 g of HCl in a total volume of 1 L. To prepare 1 L from concentrate HCl (12.1 M) dilute 833 ml of conc. HCl to 1 L.

use the equation that is standard: 1000 ml 1 M solution= (MOLECULAR WEIGHT) X ml 0.05 M solution = ((MOLECULAR WEIGHT)*X*0.05)/1000

To prepare a 1,5 M sodium chloride solution we need 87,659 g NaCl.

40 ml

49.6 mL

130mi

impossible....u want to use a low contrated solution to dilute into a higher contration solution? No way man,...

describe a precedure to prepare a 5 g standart solution of NaoH

one mole of HCl in one litre of water, result in 1M HCl

The answer is 15 mL. solution 0,2 M NaOH.

how will you prepare 0.38M sodium acetate solution

Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter

Dissolve 566.25g of KCl in 3L.

8.9g

The answer is 5 m L sodium bicarbonate, 1 M solution.

(ml NaCl )(1M NaCl) = (200ml NaCl )(0.05M NaCl ) = 10 ml

Exactly how you prepare will depend on what you are starting with. Typically to make a 1 M HCl solution, you will be starting with a stock solution of more concentrated HCl that you will then dilute. See the Related Questions for complete instructions on how to prepare a solution by diluting a stock solution. 1M HCl Solution*Concentrated HCl. its 37.5%. *The density of concentrated HCl is 1.189g/ml we will need this number as well, and of course the atomic mass of HCl 36.46 * Calculation=((37.5/100)(1000)(1.189))/36.46 = 12.2M *If HCl concentrated is 12.2 M then to make a 1L solution of 1M HCL (12.2) x = 1(1) x = 1(1)/(12.2) x=0.082ml/ml of water x = 82mL HCl per liter