Lol, I am also from U of A and was having problem with that xD Anway, here's the solution I found First of all, you add ether and acid layers (In my case, the ether is 2-methoxy-2-methylpropane and my acid is 5%HCl). Ether layer help dissolve neutral napthlanene and acid helps dissolve ethyl 4-aminobenzoate. Now separate two layers. Keep in mind that aquaous layer contains 4-aminobenzoate in ionic form and organic layer contains naphthalene. You then add excess base (10%NaOH in my case) to aquaous layer because at this point aqueous layer contains ethyl 4-aminobenzoate in of of ethyl 4-aminobenzoatehydrochloride (The structure is very similar to ethyl 4-aminobenzoate, except that it has H+ and Cl- ions attached to the component of "NH2", which makes it "NH3+Cl-" at that component). Once the layer has turned basic, ethyl 4-aminobenzoate will be isoloated out.
First, dissolve the mix in an organic solvent. Then, put in a sep funnel and wash the solution with sodium hydroxide. This will change the alpha naphthol to a sodium salt, and leave the benzophenone in the layer of organic solvent.
ehy
The melting point for lauric acid is about 45 degrees while it is 121 degrees for naphthol. So, in a mixture repeated cycles of slow warming and cooling should separate out lauric acid from naphthol. You can improve the efficiency by adding a dash of slightly acidic 70% isopropyl alcohol. This will deprotonate the lauric acid while maintaining the proton on naphthol during this process to enhance separation and purification of the two compounds. You could also flat-out distill the two products by maintaining the temperature of the solution at the boiling point of lauric acid to separate it from naphthol.
The melting point of alpha naphthol is 95-96 oC.
alpha naphthol with CCl4(carbon tetrachloride) gives blue colour whereas beta naphthol with CCl4 gives no colour. that is the distinction test between alpha and beta naphthol.
when it is kept in acid media,the acid hydrolyses the glycosidic bond and yields monosaccharide to give furfural and its derivatives ,these products when react with alpha naphthol (sulphonated) they give a purple complex
Alpha naphthol is used in the Molisch test to detect the presence of carbohydrates. Dissolving absolute ethanol in a 5 percent alpha naphthol solution helps to enhance the reaction and improve the sensitivity of detecting carbohydrates. The ethanol acts as a solvent to dissolve the alpha naphthol and create a reagent that can easily react with the carbohydrates in the test sample.
benzophenone + NH3OHCl --> benzophenone oxime (+acid) ---> beckmann rearrangement --> benzanilide
the compounds other than alpha-naphthol can be used as a reagent for the Molisch's test are the love formula.
Benzophenone is partially soluble in hexane. Benzophenone is polar, where as, hexane is nonpolar. "Like dissolves like."
what is the intermediate after adding H2SO4 on naphthol?
The melting point of phenylazo- beta-naphthol is somewhere from 131 to 133 degrees Celsius. Phenylazo- beta-naphthol is also called as Sudan I.
From least to most polar: biphenyl >> benzophenone >> benzhydrol
The question here is asked in a slightly incorrect manner. Assuming I understand exactly what you meant to ask which is "In a reduction of Benzophenone is Diphenylmethanol created with a 1/1 molar ratio?" then the answer is yes they are. For every mole of benzophenone one mole of diphenylmethanol is created. Benzophenone is a reagent and diphenylmethanol is a product in a reduction of benzophenone reaction. However if you're referring to a reaction which creates BOTH diphenylmethanol and benzophenone as products, then you would need to provide the reagents that create the two.