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The area of similar figures is proportional to the square of any linear measurement. (And all linear measurements are directly proportional.) Thus, if the ratio of the perimeters is 5/4, the ratios of the lengths of sides is also 5/4. The ratio of the areas, on the other hand, is (5/4)2, so you can simply multiply the area of the smaller square by this factor.

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Q: How do you solve the ratio perimeters of two smaller squares is 5 to 4 if the area of the smaller square is 32 square units what is the area of the larger square?
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How many squares can you make with twelve matches?

five. four smaller squares in a 2x2 formation, which then make up a larger square.


How many 5 inch squares are in 36 inch square?

There are 144 five-inch squares in a 36-inch square. You can calculate this by dividing the area of the larger square (36 * 36 = 1296 square inches) by the area of the smaller square (5 * 5 = 25 square inches) to determine how many small squares can fit inside the larger square.


How can I divide a square with an area of 144 square inches into 12 equal sized squares if it is possible?

You cannot. If you are dividing any square into equal sized squares, then the number of these smaller squares must be a square number.


What are two different size squares that the ratio of their perimeters is the same as the ratio of their areas?

Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.


How many one centimeter squares are contained in a larger square that is 10cm long and 10cm wide?

Area of small square = 1cm * 1cm = 1 cm2 Area of larger square = 10cm * 10cm = 100 cm2 Number of small squares in larger square = 100/1 = 100.

Related questions

The ratio of the perimeters of two similar squares is 5 to 4. If the area of the smaller square is 32 Square Units what is the area of the larger square?

50


Do square represent perimiter?

No, squares do not represent perimeters.


How many times larger is the area of the larger square in comparison to the smaller square?

If the length of each side of the bigger squares is x times the length of the side of the smaller square, then the area of the bigger square is x2 times the area of the smaller square.


How many squares can you make with twelve matches?

five. four smaller squares in a 2x2 formation, which then make up a larger square.


What happens if a squares perimeter is 16.4 what is the size of the rest of the perimeters?

If a square's perimeter is 16.4 - it's sides are 4.1


How many seconds on EKG paper does each large block of 5 small squares represent?

The larger square is 0.2 seconds and the smaller squares are 0.04 seconds!


The sum of two numbers is 24 find the numbers whose squares are to be minimum?

12 and 12, whose squares will be 144 each. If either of the numbers is smaller than 12, then the other will be larger than 12 and its square will be larger than 144.


What figure has 24 squares?

A Square which has been divided up into 24 smaller squares.


How big is 10 square feet?

Ten square feet is a little larger than a square yard, and a little smaller than a square meter. It is the area that would be covered by ten individual 1-foot squares.


How many 5 inch squares are in 36 inch square?

There are 144 five-inch squares in a 36-inch square. You can calculate this by dividing the area of the larger square (36 * 36 = 1296 square inches) by the area of the smaller square (5 * 5 = 25 square inches) to determine how many small squares can fit inside the larger square.


How can I divide a square with an area of 144 square inches into 12 equal sized squares if it is possible?

You cannot. If you are dividing any square into equal sized squares, then the number of these smaller squares must be a square number.


How is 4 the maximum number of nonoverlapping squares with sides of length 3 that will fit inside of a square with sides of length 6?

Each of the four squares, combined, must have a perimeterwhich adds up to that of the larger square. Since the larger square has a perimeter of 24, so must these squares. However, since we are placing them next to each other, the 2 sides of each square facing other sides do not count. Each individual square has a perimeter of 12, so that makes 48. Subtracting the lengths of the sides placed adjacent to each other (8 sides x a length of 3 = 24), we get a perimeter of 24, the perimeter of the larger square. Because the perimeters are equal, there is no room left for another square without overlapping.