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How do you solve x³-4x equals 0 algebraically?


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Answered 2010-10-17 20:54:08

Suppose x3-4x = 0. To solve, factor:

x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve.

The roots are 0,-2 and +2.

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