How do you store a number of integers entered by the user in an arra with C?

Answer 1

You can use dynamic arrays. Malloc, realloc and free play crucial roles. You can also substitute calloc for malloc. Below is a sample code:

#include

#include

int

main(){
int

n = 10

, noofnumbers = 0

, num, i;

int

*arr = (

int

*)malloc(n*

sizeof

(

int

));

//first creating an array of size 10 - you can even skip this part and directly go for expanding an array every time an element is entered
if

( !arr ){
printf(

"No space in memory\n");

return

(1

);
}
while

( scanf("%d"

, &num) != EOF){
if

( noofnumbers < n){
arr[noofnumbers] = num;
noofnumbers++;
}

else

{

//when more than 10 numbers are added increasing the size accordingly
int

*temp = (int

*) realloc(arr, (++n)*sizeof

(int

));//realloc for reallocating the memory
if

( temp == NULL

){
printf("Not enough space\n"

);
break

;
}
else

{
arr = temp;
arr[noofnumbers] = num;
noofnumbers++;
}
}
}
printf(

"the numbers are:\t");

for

( i = 0

; iprintf("%d\t"

, arr[i]);
printf("\n"

); free(arr);//freeing the memory space
return

0

;

}