1. Calculate the mean average of the N numbers. Suppose it is stored in the variable D.
2. Now calculate the differences between each number with D and square the value. As there are N numbers so store this difference in an array. Example arr[0] = (num0 - D)^2; arr[1] = (num1 - D)^2; arr[N-1] = (numN - D)^2;
3. Now sum array value and divide by N, suppose the value is stored in F. Now square root F. It is the standard deviation of your N number.
I hope you can write the code by yourself or follow the part:
suppose you will store the N numbers in an array num. Now:
int num[N+2], D = 0; //or declare the num array as float or double if there are any precision value
for(int i = 0; i < N; i++)
{
D += num[i];
}
D /= N;
int arr[N+2];
for(int i = 0; i < N; i++)
{
arr[i] = (num[i] - D)^2; //square the difference.
}
int F = 0; //if precision value is accepted then declare F as float or double not int.
for(int i = 0; i < N; i++)
{
F += arr[i];
}
F /= N;
F = sqrt(F); //use #include <cmath> in your header file list so that you can use sqrt() function or simply use #include <bits/stdc++.h>
cout<<F<<endl;
- Thanks
Write a program to calculate the standard deviation of an array of values.
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Exactly as in the question: standard deviation!
Exactly as in the question: standard deviation!
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