How do you write a java program to print numbers that have number nine up to 100?

Answer 1

Solution 1

public class Divisible {

int num;

int sum;

public void calculate() {

sum=0;

System.out.println("Numbers divisible by 9:");

for(num=50;num<100;num++) {

if(num%9==0) {

System.out.println(num);

sum=sum+num;

}

}

System.out.println("Sum: "+sum);

}

public static void main(String a[]) {

Divisible obj=new Divisible();

obj.calculate();

}

}

Solution 2public static void printNums() {
// We know that 54 is the first number in the range divisible by 9.
// So if we start there and add 9, we will quickly find all numbers
// in the given range which are evenly divisible by 9.

for( int i = 54; i <= 100; i += 9 ) {
System.out.println(i);

}

}

Answer 2

public class TestMain {

/**

* @param args

*/

public static final void main(String[] args) {

int sum = 0;

int count = 0;

for (int i = 100; i <= 200; i++){

if(i%7 == 0){

count++;

sum = sum + i;

System.out.println("The number is: " + i);

}

}

System.out.println("Number of values divisible by 7 between 100 and 200 is: " + count);

System.out.println("Sum of values divisible by 7 between 100 and 200 is: " + sum);

}

}

Output:

The number is: 105

The number is: 112

The number is: 119

The number is: 126

The number is: 133

The number is: 140

The number is: 147

The number is: 154

The number is: 161

The number is: 168

The number is: 175

The number is: 182

The number is: 189

The number is: 196

Number of values divisible by 7 between 100 and 200 is: 14

Sum of values divisible by 7 between 100 and 200 is: 2107

Answer 3

Convert the number to a string then test the string to see if the character '9' is present. If so, convert back to a number and print it.