Java program to find compound interest?

Answer 1

public class SimpleInterest{

float principal,intRate, numOfYears;

public void setPrincipal(float principal){

this.principal = principal;

}

public void setIntRate(float intRate){

this.intRate = intRate;

} public void setNumOfYears(float numOfYears){

this.numOfYears = numOfYears;

} public float calculateSimpleInterest(){

return (this.principal * this.intRate * this.numOfYears) /100; } public static void main(String argv[]){

float principal,intRate, numOfYears;

SimpleInterest simpIntObj = new SimpleInterest();

principal = Float.parseFloat(argv[0]);

intRate = Float.parseFloat(argv[1]);

numOfYears = Float.parseFloat(argv[2]);

simpIntObj.setPrincipal(principal);

simpIntObj.setIntRate(intRate);

simpIntObj.setNumOfYears(numOfYears);

System.out.println ("Principal = "+principal);

System.out.println ("Interest Rate = "+intRate);

System.out.println ("Num of Years = "+numOfYears);

System.out.println ("Simple Interest Amount = "+simpIntObj.calculateSimpleInterest());

} }

Answer 2

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

float p,t,r;

float i,ci,a;

clrscr();

printf("enter the principal:\t");

scanf("%f",&p);

printf("enter the rate of interest:\t");

scanf("%f",&r);

printf("enter the time in years:\t");

scanf("%f",&t);

if((p<0)(t<0)(r<0))

printf("invalid");

else

{

i=(p*t*r)/100.0;

printf("the simple interest is rs.%.2f",i);

a=(float)p*(pow(1+r/100.0,t));

ci=a-p;

printf("the compound int is rs.%.2f",ci);

}

getch();

}

Answer 3

public doublecalculateInterest (intprinciple, int rate, int numOfYears) {

doubleinterest = (principle * rate * numOfYears)/ 100;

return interest;

}

Answer 4

double futurevalue = Principle*Math.pow (1 + interest, numberofyears);

I think maybe :)

Answer 5

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