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Yes as long as the value of the string is an integer. String str = "12345"; int i = Integer.parseInt(str); Note: This code would work very well for strings that have numeric values inside. If your string can contain any kind of data, remember to surround this code with a try catch block to ensure that you don't get an exception that crashes your system. Some of us usually miss the try catch block expecting ideal input. But once in a while we get some data that is different to what we are expecting in our code which crashes our system. Instead of spending hours trying to figure out what crashed our app, its easier to have a catch block do the work :)

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Wiki User

15y ago
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Wiki User

14y ago

If one needs to get the ascii value of a char, a cast to int will do it.

char c='A';

int a=c; // a = 65 now

If you are talking of getting the number 1 from the char '1', then this is one way I can think of:

char c='1';

int a=Character.digit(c, 10);

xcvxcvxcv

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Wiki User

13y ago

It depends.

if you are using String to Integer,

int num = Integer.parseInt( str );

where num is your integer variable, and str is your string variable.

you can also use

double num = Double.parseDouble( str ), etc.

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Wiki User

8y ago

You can use Java Wrapper class to do this. You can use Integer Wrapper to create integer object and then use toString() to convert to String.

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Wiki User

10y ago

One may convert a string to an integer (int) in Java programming by using the "parseInt()" function. A complete programming example is available i s available on "Stack Overflow".

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Wiki User

10y ago

String can be converted into int Java: if the string numbers are ABCD, int foo = Integer.parseInt(ABCD). Knowledge of Java is important to understand these conversions.

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14y ago

This is extremely simple: just concatenate the integer with a String. Example: String myText = "My age is " + age; // or, if you don't want to include any text: String myText = "" + age;

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Anonymous

Lvl 1
4y ago

Exercise 19.8 Answer each of the following questions briefly. The questions are based on

the following relational schema:

Emp(eid: integer, ename: string, age: integer, salary: real, did: integer)

Dept(did: integer, dname: string, floor: integer)

and on the following update command:

replace (salary = 1.1 * EMP.salary) where EMP.ename = ‘Santa’

1. Give an example of a query that would conflict with this command (in a concurrency

control sense) if both were run at the same time. Explain what could go wrong, and how

locking tuples would solve the problem.

2. Give an example of a query or a command that would conflict with this command, such

that the conflict could not be resolved by just locking individual tuples or pages, but

requires index locking.

3. Explain what index locking is and how it resolves the preceding conflict.

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Q: How does one use string to int Java?
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Which is the best way to convert numbers in string under java?

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Related questions

How can someone convert string to int in Java?

To convert string to int in Java, the easiest way is to simply use the method Integer.parseInt(). For more information how to do this, refer to the integer class documents.


In java how do you use a for loop to print out a word as many times of its length?

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How do you use indexOf in java?

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Which is the best way to convert numbers in string under java?

All of the Java number classes have a parse[type] method, like parseInt() in Integer or parseDouble() in Double that convert Strings to primitive numbers. String s = getInput(); int var = Integer.parseInt(s);


What is member variable in java?

We use the term member variable to refer to variables that are defined inside a method. Ex: public String getName(){ String x = "ttt"; ..... } In the method getName() x is a member variable


How can you convert byte to string in java?

To convert byte to String in java use the String(bytes, UTF-8); //example for one encoding type. You must know the special encoding that contains a variety of characters.


Why we use IntegerParseInt in java?

Parsing is very important since the input from the user is not in the form of ints but in a String, therefore, you have to parse the String containing the number into a primitive data type. i.e. String num = "49"; int realNum = Integer.parseInt(num); // puts 49 into realNum;


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Use "+". Example: String string = "does this answer " + "your question?";


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