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How can the electrical potential energy of a charged particle in an electric field be increased?
Wiki User
∙ 13y ago
THIS IS A GOOD QUESTION IF WE PLACE THE CHARGE IN THE ELECTRIC FIELD AT A DISTANCE R FROM THE ELECTRIC FIELD AND PLACED THE ANOTHER POINT CHARGE AT A ANOTHER DISTANCE r WHERE R IS GRATER THAN THE SMALL R THEN THE ELECTRIC FIELD AT r IS MORE THAN THE ELECTRIC FIELD AT POINT R.
OR
WE CAN SAY THAT IF THE CHARGE IS PLACED IN THE DIRECTION OF ELECTRIC FIELD THAN ITS ELECTROSTATIC POTENTIAL ENERGY WILL DECREASE OR WHEN IN DIRECTION OPPOSITE THAN VICEVERSA
Wiki User
∙ 13y ago
Wiki User
∙ 13y agoWe can increase the electric potential energy by increasing the voltage through power supply.
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How does the electric potential energy between two charged particles change if one particle's charge is increased by a factor of 2?
It is increased by a factor of 2
How does the electric potential energy between two charged particles change if one particles charge is increased by a factor of two?
It is increased by a factor of 2
What has potential energy?
Potential energy is a energy stored within a system as a result of the position or configuration of the different parts of that system.The types of potential energy are gravitational potential energy, which is energy due to height, and elastic potential energy, which is energy involved with a stretched or compressed spring.
Electricity is dependent upon what?
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
If a proton moved from 0 V potential to 5 V potential would its potential energy increase or decrease?
Electric field points from high potential to low potential. Positive particles had tendency to follow electric field. If you are moving the particle against this tendency you are doing work, and this work give more potential energy to the particle.
How does the electric potential energy between two charged particles change if one particle's charge is increased by a factor of 2?
It is increased by a factor of 2
How does the electric potential energy between two charged particles change if one particles charge is increased by a factor of two?
It is increased by a factor of 2
What is electric potential dependent upon?
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
What Electrical potential energy?
Electric potential is like electric potential energy, except electric potential energy requires that you have at least two charged particles: one charged particle (can be considered to be stationary) to produce the electric field and another charged particle to be affected by that electric field. If both charged particles are positively charged, then when you move the nonstationary charged particle closer to the stationary charged particle, potential energy of the system increases, because the charged particles naturally want to repel. However, let's say you remove that nonstationary charged particle and are left with just the single charged particle. There is no more potential energy in the system, because there is no other charged particle to be acted upon by the electric field. However, the single charged particle still emits an electric field. This field is what creates "electric potential." Even though there is no second particle in the system, if you were to place a second particle into the system (let's call it a test particle), its potential energy would be equal to the electric potential multiplied by the charge of the test particle. U = kq1q2/r (electric potential energy with 2 charges, where the 0 of potential energy is infinitely far away) V = kq1/r (electric potential requiring only 1 charge) V = U/q2 (electric potential is potential energy without the second charge) U = Vq2 (electric potential energy is electric potential multiplied by second charge) There is also a concept called gravitational potential, where it's gravitational potential energy divided by the test mass. It can be a negatively charged particle. In that case, electric potential decreases as you get closer to the negatively charged particle. Even though electric potential decreases, if you have two negatively charged particles, electric potential energy increases as you move the 2nd negative charge closer to the first charge. This is because multiplying 2 negative charges makes a positive: U = k(-q1)*(-q2)/r = kq1q2/r (assuming q1 and q2 are the charge magnitudes) So in this case, it's a little weird because that's how the math works. Nature has a tendency to reduce potential energy, but potential is different and doesn't work the same way. However if the test charge was positive, the sign of electric potential energy will be the same as electric potential with respect to location. V = k(-q1)/r = -kq1/r U = k(-q1)(q2)/r = -kq1q2/r Potential energy is not the same as potential! They are related, but don't get them confused. Energy is measured in Joules. Potential is measured in Volts. Completely different units. Volts = Number of Joules / Number of Coulombs. Electric Potential = Electric Potential Energy / Charge of Test Particle
What does electrical potential mean?
Electric potential is like electric potential energy, except electric potential energy requires that you have at least two charged particles: one charged particle (can be considered to be stationary) to produce the electric field and another charged particle to be affected by that electric field. If both charged particles are positively charged, then when you move the nonstationary charged particle closer to the stationary charged particle, potential energy of the system increases, because the charged particles naturally want to repel. However, let's say you remove that nonstationary charged particle and are left with just the single charged particle. There is no more potential energy in the system, because there is no other charged particle to be acted upon by the electric field. However, the single charged particle still emits an electric field. This field is what creates "electric potential." Even though there is no second particle in the system, if you were to place a second particle into the system (let's call it a test particle), its potential energy would be equal to the electric potential multiplied by the charge of the test particle. U = kq1q2/r (electric potential energy with 2 charges, where the 0 of potential energy is infinitely far away) V = kq1/r (electric potential requiring only 1 charge) V = U/q2 (electric potential is potential energy without the second charge) U = Vq2 (electric potential energy is electric potential multiplied by second charge) There is also a concept called gravitational potential, where it's gravitational potential energy divided by the test mass. It can be a negatively charged particle. In that case, electric potential decreases as you get closer to the negatively charged particle. Even though electric potential decreases, if you have two negatively charged particles, electric potential energy increases as you move the 2nd negative charge closer to the first charge. This is because multiplying 2 negative charges makes a positive: U = k(-q1)*(-q2)/r = kq1q2/r (assuming q1 and q2 are the charge magnitudes) So in this case, it's a little weird because that's how the math works. Nature has a tendency to reduce potential energy, but potential is different and doesn't work the same way. However if the test charge was positive, the sign of electric potential energy will be the same as electric potential with respect to location. V = k(-q1)/r = -kq1/r U = k(-q1)(q2)/r = -kq1q2/r Potential energy is not the same as potential! They are related, but don't get them confused. Energy is measured in Joules. Potential is measured in Volts. Completely different units. Volts = Number of Joules / Number of Coulombs. Electric Potential = Electric Potential Energy / Charge of Test Particle
How electrical potential produce?
Electric potential is like electric potential energy, except electric potential energy requires that you have at least two charged particles: one charged particle (can be considered to be stationary) to produce the electric field and another charged particle to be affected by that electric field.If both charged particles are positively charged, then when you move the nonstationary charged particle closer to the stationary charged particle, potential energy of the system increases, because the charged particles naturally want to repel.However, let's say you remove that nonstationary charged particle and are left with just the single charged particle. There is no more potential energy in the system, because there is no other charged particle to be acted upon by the electric field. However, the single charged particle still emits an electric field. This field is what creates "electric potential." Even though there is no second particle in the system, if you were to place a second particle into the system (let's call it a test particle), its potential energy would be equal to the electric potential multiplied by the charge of the test particle.U = kq1q2/r (electric potential energy with 2 charges, where the 0 of potential energy is infinitely far away)V = kq1/r (electric potential requiring only 1 charge)V = U/q2 (electric potential is potential energy without the second charge)U = Vq2 (electric potential energy is electric potential multiplied by second charge)There is also a concept called gravitational potential, where it's gravitational potential energy divided by the test mass.It can be a negatively charged particle. In that case, electric potential decreases as you get closer to the negatively charged particle. Even though electric potential decreases, if you have two negatively charged particles, electric potential energy increases as you move the 2nd negative charge closer to the first charge. This is because multiplying 2 negative charges makes a positive:U = k(-q1)*(-q2)/r = kq1q2/r (assuming q1 and q2 are the charge magnitudes)So in this case, it's a little weird because that's how the math works. Nature has a tendency to reduce potential energy, but potential is different and doesn't work the same way.However if the test charge was positive, the sign of electric potential energy will be the same as electric potential with respect to location.V = k(-q1)/r = -kq1/rU = k(-q1)(q2)/r = -kq1q2/rPotential energy is not the same as potential! They are related, but don't get them confused. Energy is measured in Joules. Potential is measured in Volts. Completely different units.Volts = Number of Joules / Number of Coulombs.Electric Potential = Electric Potential Energy / Charge of Test Particle
How do you know microscopically that potential energy of the particle has increased?
Potential energy might be thought of as the potential for a body to gain kinetic energy if allowed to move. A ball held several feet above the surface of the earth has potential energy because if it is released, gravity will cause it to fall and acquire kinetic energy - or more accurately - convert the potential energy into kinetic energy. The amount of potential energy is determined by the position of the body relative to the source of the force acting on it. Some sources of forces include gravity, magnetism, and electrical charge. On a microscopic scale, we can tell that the potential energy of a particle has increased if it has moved farther from the source of the force. It would also gain potential energy if the magnetic strength increased (when magnetism is creating the force) or the charge increased (when charge is creating the force). Note that in the case of gravity, the mass of the source of the gravity would have to increase since if the mass of the particle increased, it would be a different particle.
What has potential energy?
Potential energy is a energy stored within a system as a result of the position or configuration of the different parts of that system.The types of potential energy are gravitational potential energy, which is energy due to height, and elastic potential energy, which is energy involved with a stretched or compressed spring.
What is the space around a particle through which an electric can exert its force?
The answer is an electrical field.
The energy a particle possesses due to its position relative to other charged particles?
electric potential energy
How do you know macroscopically that the potential energy of the particle has increased?
It is not possible to know that I'm afraid :(
Electricity is dependent upon what?
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
