It depends on the load.
yes, the 5ah battery will last 5/3 longer than the 3ah battery.
There is not enough information. It depends on the type of battery: chemistry, cells, size.
Yes you can. The charger has what is called a trickle charge and will need to be left charging at least overnight and maybe for two nights dependant on how little charge the battery has left.
54 Lombard StreetLondonEC3P 3AH
The location for Baylis Court School is in Gloucester Avenue SloughSL1 3AH.
LDA is an Intel 8085 opcode, 3AH, that loads that accumulator from a location specified in memory.
Write a program using the ADI instruction to add the two hexadecimal numbers 3AH and 48H and store the result in memory location 2100H
1/3Ah That is to say, 1/3 times the area of the base times the height (not the slant height) of the cylinder
v=1/3Ah (ex.1/3*6*8=??) 6 is equal to the variable A 8 is equal to the variable h
In the 8085, the LDA instruction loads the accumulator from memory, while the STA instructionstores the accumulator to memory. LDA is a read, while STA is a write. LDA is opcode 3AH, while STA is opcode 32H.
In the 8085, the LDA instruction loads the accumulator from memory, while the STA instruction stores the accumulator to memory. LDA is a read, while STA is a write. LDA is opcode 3AH, while STA is opcode 32H.
The formula for the area of a square based pyramid is: V=1/3AH V being the volume, A the area of the base and H being the height. Substituting your values (although I'm not totaly sure what you mean by 'cubic units' as that refers to a volume, not a length) we get this: V=1/3 x 92x s Simplifying this we get: V=27s Therefore the answer to your question in 27s cubic units (this is what I get assuming that cubic units may have been a typo etc...). An alternative would be to substitute the cube root of 9 into the formula, when we do this we get: V= (92/3s)/3 Simplifying this we get: V=1.44224957s So an alternative answer is 1.44s cubic units (2dps) I hope this helps