There are zero amps in a 300 watt bulb. Watts are the product of amps times volts. W = A x V. To find amperage use the equation A = W/V. If you find the voltage of the 300 watt bulb uses, divide the wattage by the voltage and it will give you the amps of a 300 watt bulb.
4170 @ 120 volts (266 watts)
6120 @ 130 volts (300 watts)
A 300-watt bulb or a 300-watt gzornenplatz both use the same amount of power, 300 watts. In one hour they would use 300 watt-hours of energy, equal to 0.3 kilowatt-hours.
If left on for four hours it would use 1.2 kWh of power.
amps equals watts divided by volts.
figure out how many amps are in a watt and x by 40
Watts = Volts x Amps for an incandescant bulb. So Amps = 600/120.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
draw 0.104 amps
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
A 120 volt table lamp with a 75 watt bulb will pull 0.625 amps. With a 100 watt bulb it will pull 0.833 amps. And with a modern fluorescent 13 watt bulb it will pull 0.108 amps.
figure out how many amps are in a watt and x by 40
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
Watts = Volts x Amps for an incandescant bulb. So Amps = 600/120.
It is drawing .06 amps.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
draw 0.104 amps
amps equals watts divided by volts.
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
Look on the light bulb for the voltage and the power in watts. Then divide the watts by the voltage and that gives the amps. Some CFL bulbs also state the current as well as the voltage and power, which is because they can have a poor power factor.
You just have to divide the watts by the voltage to find the amps. For example 60 watts on a 120 v system would take ½ amp.
To answer this question the voltage of the bulb is needed.