Minimum current would be 10000 divided by 240 but it might be up to 30% more if the load has a poor power factor.
41.66
The amperage drawn from a C cell battery is governed by the load resistance. The lower the resistive load the higher the amperage draw from the battery.
Remember that watts are voltage x current(amps) The number of watts you can get from a 48V battery will depend on how many amps the battery can deliver and how much the load can draw.
41.666 amps. Divide watts by volts.
draw 0.104 amps
40 amps
10000 divided by 220 for a resistive load.
Minimal 100. Depends on load draw of home. Can be 200 amps or 400 amps as well.
The amperage drawn from a C cell battery is governed by the load resistance. The lower the resistive load the higher the amperage draw from the battery.
Remember that watts are voltage x current(amps) The number of watts you can get from a 48V battery will depend on how many amps the battery can deliver and how much the load can draw.
41.666 amps. Divide watts by volts.
draw 0.104 amps
Then you are trying to get more HP out of the motor that it can supply. Back off on the load that the motor is driving or put a bigger motor onto the load.
The answer you are looking for is on the condensing unit tag. It`s listed as FLA or (full load amps) or RLA (running load amps). Start up amps are appx 5 to 6 times this # but this current is only drawn very briefly. Be sure to add both the compressor and fan motor amperage to get total current draw of the unit. The control power is supplied by the indoor unit so that is not a factor.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
40 amps
There are zero amps in 3000 volts. A load needs to be connected to the voltage.
100 amps