Amps = Watts/Volts
55/12= 4.583333
The amps are equal to the watts divided by the volts, in this example 50 divided by 12.
To answer this question the wattage of the bulb is needed.
Divide the watts by the voltage - answer 8.333 amps
2.92
50W@12V is 4.2 amps, so any breaker rated that or higher should work.
Volts * Amps = Watts 12V * A = 150W A = 150W/12V A = 12.5
Volts * Amps = Watts 12 V * ?Amps = 100 Watts OR ? Amps =100W/12V OR 8.33 Amps = 100W/12V Use a 10Amp fuse inline and you can get by with 16Ga wire.
P=VI => I=P/V => I=60W/12V => I=5A 5 amps when the globe is operating
The formula you are looking for is I = W/E. Amps = Watts divided by Volts.
Watts and amps measure different aspects of electricity and are not interchangeable.
50W@12V is 4.2 amps, so any breaker rated that or higher should work.
Volts * Amps = Watts 12V * A = 150W A = 150W/12V A = 12.5
Volts * Amps = Watts 12 V * ?Amps = 100 Watts OR ? Amps =100W/12V OR 8.33 Amps = 100W/12V Use a 10Amp fuse inline and you can get by with 16Ga wire.
well the equation for amps is a= watts/volts so 25/12= 2.0833333333amps
About 0.6 amps for a 12v 21w bulb
yes my honda phantom has 12v 55 watt headlight
160 amps at 12v.
160 amps at 12v.
Just connect the circuit. It will only draw the amps it needs to operate. It is just like connecting a 100 watt light bulb that draws way less than 1 amp, to a 20 amp household circuit.
Not enough to worry about. That's like asking how many amps does the memory preset's on your radio draw. It is in the .001-.01 range.
P=VI => I=P/V => I=60W/12V => I=5A 5 amps when the globe is operating