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3.14 g Cu = # atoms
Take the known mass of copper multiply it by Avogadro number and divided by the atomic weight.
Atomic weight of copper:
63.5 g
3.14 g Cu (6.02 × 1023 atoms) / (63.5 grams) = 2.98 × 1022 atoms of Copper
Wiki User
∙ 15y ago
Wiki User
∙ 15y agoFor this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.
3.14 grams Cu / (63.5 grams) × (6.02 × 1023 atoms) = 2.98 × 1022 atoms
Wiki User
∙ 12y ago[ 10.4333 (g Cu) / 63.55 (g/mol Cu) ] * 6.022*10+23 (atoms/mol) = 98.87*10+21 atoms
Wiki User
∙ 7y ago29
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How many atoms are present in 6.81g of copper?
6.81 grams copper (1 mole Cu/63.55 grams)(6.022 X 1023/1 mole Cu) = 6.45 X 1022 atoms of copper ----------------------------------------
How many atoms would be found in 1.2 grams of copper?
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
How many Cu atoms are present in a piece of sterling-silver jewelry weighing 33.14 g?
This depends on the percentage of copper in the alloy.If this alloy contain 7,5 % Cu the number of copper atoms is approx. 0,2355.10.e+23.
How many atoms are in CuNO3 2?
Cu(NO3)2 has 9 atoms 1 Cu atom 2 N atoms 6 O atoms
How many atoms are in CU(NO3)2?
1 w
How many atoms are present in 6.81g of copper?
6.81 grams copper (1 mole Cu/63.55 grams)(6.022 X 1023/1 mole Cu) = 6.45 X 1022 atoms of copper ----------------------------------------
How many atoms would be found in 1.2 grams of copper?
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
How many Cu atoms are present in a piece of sterling-silver jewelry weighing 33.14 g?
This depends on the percentage of copper in the alloy.If this alloy contain 7,5 % Cu the number of copper atoms is approx. 0,2355.10.e+23.
How may atoms of oxygen are present in Cu(NO3)2?
Copper(II) nitrate has six oxygen atoms.
How many atoms are in CuNO3 2?
Cu(NO3)2 has 9 atoms 1 Cu atom 2 N atoms 6 O atoms
How many atoms of copper Cu are in a pure copper coin weighing 12.0 g?
Answer: 1.14x10^23 atoms Cu (12.0g Cu/63.55amu(g) Cu) Then take (Ans x 6.022x10^23) = 1.13712038x10^23 atoms Cu. Then I simplified it to 3 sig figs. = 1.14x10^23 atoms Cu Never forget your units and substance!
How many grams do 4.6 x1025 atoms of cu weigh?
I assume you mean 4.6 X 10^25 atoms. This is the conversion. 4.6 X 10^25 atoms Cu ( 1mol Cu/ 6.022 X 10^23 )( 63.55 grams Cu/ 1 mol Cu ) = 4854.37 grams Cu
How many oxygen atoms are present in a 14.0 g sample of Cu(NO3)2?
14.0 g x 1 mole/187.56 g = 0.0746 moles0.0746 moles Cu(NO3)2 x 6 moles O/mole Cu(NO3)2 = 0.448 moles O atoms0.448 moles O atoms x 6.02x10^23 atoms/mole = 2.70x10^23 atoms of oxygen
How many moles of atoms are in 450000000000000000000000 atoms of Cu?
Divide that number of atoms by 6.02x10^23 atoms/mole
How many atoms are in each elemental sample 4.0mol Cu?
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
How many atoms are in 1 mole of Copper?
1 mol Cu Atoms (6.02x10^23 atoms)
How many moles of Cu are in the 148 times 10 to the power 25 atoms?
15.8 moles Cu x 6.02x10^23 atoms/mole = 9.51x10^22 atoms. There are no molecules in the element Cu (copper). Molecules are found when there are two or more atoms bound together, such as in H2 gas or H2O, etc.
