For this problem, the Atomic Mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.
2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
4.5 moles Li (6.022 X 10^23/1 mole Li)
= 2.7 X 10^24 atoms of lithium
2.5 moles Li × (6.02 ×1023 atoms) = 1.5 × 1024atoms Li
2.5 * 6.02 * 10^23
The answer is 12,044.10e23 atoms.
Quite a few! 738 grams water (1 mole H2O/18.016 grams)(2 mole H/1 mole H2O)(6.022 X 10^23/1 mole H) = 4.93 X 10^25 atoms of hydrogen
The % of hydrogen is superfluous information 1.5 lb H2O2 (454 grams/1 lb)(1 mole H2O2/34.016 grams)(2 mole H/1 mole H2O2)(6.022 X 10^23/1 mole H) = 2.4 X 10^25 atoms of hydrogen
One Mole of C2H4 will containt 6.0221415×10^23 molecules of C2H4. Therefore 2.23 Moles of C2H4 will contain 1.39713683x10^24 molecules of C2H4. There are 4 Hydrogen atoms in C2H4, so 1.39713683x10^24 x 4 = 5.58854732X10^25 atoms of hydrogen.
1 mole of silver contains 6.022 X 10^23 atoms 62 moles of silver contains 3.73 X 10^25 atoms of silver
The answer is B, 8.0 x 10^1 There are 6.023 x 10^23 atoms in one mole, of any substance. So simply divide 4.8 x 10^25 by 6.023 x 10^23, to get about 79.69 which if you convert into scientific notation, is about 8.0 x 10^1 the answer for me was A but that's on novanet
Quite a few! 738 grams water (1 mole H2O/18.016 grams)(2 mole H/1 mole H2O)(6.022 X 10^23/1 mole H) = 4.93 X 10^25 atoms of hydrogen
593 g H2O x 1 mol/18 g x 2 mole H/mole H2O x6.02x10^23 H atoms/mole H = 4x10^25 atoms of H
The % of hydrogen is superfluous information 1.5 lb H2O2 (454 grams/1 lb)(1 mole H2O2/34.016 grams)(2 mole H/1 mole H2O2)(6.022 X 10^23/1 mole H) = 2.4 X 10^25 atoms of hydrogen
(NH4)2S 4.10 moles (NH4)2S (8 moles H/1 mole (NH4)2S)(6.022 X 10^23/1 mole H) = 1.98 X 10^25 atoms of hydrogen
2 moles C8H18 (18 moles H/1 mole C8H18)(6.022 X 10^23/1 mole H) = 2.2 X 10^25 atoms of hydrogen
20 moles x 6.02x10^23 atoms/mole = 1.2x10^25 atoms
8.70 moles (NH4)2S x 6.02x10^23 molecules/mole x 8 H atoms/molecule = 4.18x10^25 H atoms
about 1.4*10^25
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 25 mole of CO2 has 25 moles of carbon atoms and 50 moles of oxygen atoms.
One Mole of C2H4 will containt 6.0221415×10^23 molecules of C2H4. Therefore 2.23 Moles of C2H4 will contain 1.39713683x10^24 molecules of C2H4. There are 4 Hydrogen atoms in C2H4, so 1.39713683x10^24 x 4 = 5.58854732X10^25 atoms of hydrogen.
25x(2/18)=2.78g of hydrogen 25x(16/18)=22.22g of oxygen
1 mole of a substance has approximately 6.02 x 10^23 its particles. 8.1 moles of C9H20 has 8.1 x 6.02 x 10^23 = 4.8762 x 10^24 C9H20 molecules There are 20 Hydrogen atoms in a molecule of C9H20. Number of hydrogen atoms = 4.8762 x 10^24 x 20 = 9.7524 x 10^25 There are about 9.75 x 10^25 Hydrogen atoms