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For this problem, the Atomic Mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.

2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms

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15y ago
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13y ago

4.5 moles Li (6.022 X 10^23/1 mole Li)

= 2.7 X 10^24 atoms of lithium

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15y ago

2.5 moles Li × (6.02 ×1023 atoms) = 1.5 × 1024atoms Li

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15y ago

2.5 * 6.02 * 10^23

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8y ago

The answer is 12,044.10e23 atoms.

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Q: How many atoms are in 2.5 mole of hydrogen?
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