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The density of copper (Cu) is about 8.92 g/cm3. So 1 cm3 of copper is about 8.92 g. Next find the number of moles in 8.92 g of copper by dividing by its molecular weight:

8.92 g Cu / 63.54 g/mol Cu = 0.14038 mol Cu

By definition 1 mol of any substance is Avogadro's number of atoms or, 6.022 x 10 23 atoms.

So, 0.14038 mol Cu * [6.022x1023 atoms Cu / mol Cu] = 8.45x1022 atoms of Cu

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12y ago
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14y ago

For this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.

1.2 kg = 1200 g

1200 grams Cu / (63.5 grams) × (6.02 × 1023 atoms) = 1.14 × 1025 atoms

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14y ago

10.4 grams Copper (1mol Cu/63.55g)(6,022 X 10^23/1mol Cu ) = 9.86 X 10^22 atoms

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7y ago

1 kg Copper = 1000 g Copper
1000 g copper x 1 mole copper/63.5 g x 6.02x10^23 atoms/mole = 9.48x10^24 atoms
Answer would be 9x10^24 atoms to 1 significant figure

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11y ago

d.

1.14

´

1023atoms

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12y ago

2.84*10^25

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Q: How many atoms in 1 cm3 of copper?
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