The molar mass of water(H2O)=18((1*2)+16)
The no. of moles(n) of water in 18 g of water=mass/molar mass=18 g/ 18 g mol-1 =1 mol
The no. of molecules of water in 18 of water=n*Avogadro no. =1 mol*6.022*1023 mol-1 =6.022*1023
The no. of atoms of oxygen in one mole of water=1 mol
The no. of atoms of oxygen in 6.022*1023mol of water= 6.022*1023
how many grams of oxygen in 18 grams of water
602,000,000,000,000,000,000,000 (6.02 X 10^23) Oxygen atoms.
How many grams of Na+ are contained in 25 g of sodium sulfate (Na2SO4)?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
First find the percentage by mass of oxygen in water. The formula for water is H2O, showing that water contains two hydrogen atoms for every atom of oxygen. The gram atomic masses of hydrogen and oxygen are 1.00794 and 15.9994 respectively. Therefore, the percentage of oxygen in water is 100{15.9994/[15.9994 + 2(1.00794)]} or about 88.8 %, to the justified number of significant digits; the ratio of the maximum mass of water that can be made from a given mass of oxygen is 1/0.888 or about 1.126; and the answer to the question is this number multiplied by the stated mass of oxygen, or 24.9 grams, to the justified number of significant digits.
16.0 g
1.10x10^24
20.6g
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
1 mol of oxygen is 16.00g. Therefore 2.43g of oxygen would contain 0.152 mols of oxygen. (2.43g/16.00g)
how many grams are contained in 11.89 pounds?
67.5 grams of H2O
25.78g
25
The answer is 165,5 g water.
5,393.213 grams.
9394.1 grams
192.2mg is 0.1922 grams.
The mass fraction oxygen in water is 0.8881.m oxygen = ( 0.8881 ) ( 0.18 g H2O ) = 0.16 g oxygen in 0.18 g of H2O