3 moles of Ca would have 1.806 × 10^24 atoms.
3 x 6.02E23 molecules.
Ca (NO3)2 So the number of Ca atoms will just be Avogadro's constant, L
12.7 moles calcium (6.022 X 10^23/1 mole Ca) 7.65 X 10^24 atoms of calcium in 12.7 moles.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
2 moles of Ca and 4 moles of OH
425 g calcium (Ca) is equal to 10,604 moles.
44 moles of atoms
1.34 moles Ca x 6.02x10^23 atoms Ca/mole Ca = 8.07x10^23 atoms of Ca
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
Ca!
Ca (NO3)2 So the number of Ca atoms will just be Avogadro's constant, L
1mol Ca = 40 gCa 45.8g/40g = 1.145 mol Ca
The atomic mass of calcium, Ca is 40.1. First we calculate the amount in moles of calcium in a 98.5g pure sample.Amount of Ca = 98.5/40.1 = 2.46mol So there are 2.46 moles of Ca (or Ca atoms).
12.7 moles calcium (6.022 X 10^23/1 mole Ca) 7.65 X 10^24 atoms of calcium in 12.7 moles.
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.