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The standard IPv4 (internet Protocol version 4) address currently in use almost everywhere is a 32-bit number split into 4 8-bit values displayed as decimal numbers separated by periods. It is often referred to as a "dotted quad" (as in 192.168.3.24). None of the values should have a leading zero as it may be interpreted as a hexadecimal number (as in 192.168.3.024 and hex 024 will be used as decimal 36). An IPv4 address is split into a network number (your home or company) and a host (each individual machine on your network). The addresses are assigned to classes where class A, B, and C represent different network host capacities. Class D and E are reserved

There is a newer standard IPv6 (Internet Protocol version 6). An IPv6 address has 128 bits split into 8 groups of 16 bit values displayed as a hexadecimal numbers separated by colons (as in 3f45:1c65:05ab:babe:0000:0000:feed:0041). To simplify things, leading zeros can be removed (as in 3f45:1c65:5ab:babe:0:0:feed:41) and all zero entries can be removed altogether (as in 3f45:1c65:5ab:babe:::feed:41).

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8y ago
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14y ago

In general, both IPv4 and IPv6 are in use today so they are both current. IPv4 is still the standard for implementation of the Internet Protocol, however IPv6 has a much larger address space:

IPv4 is a 32-bit address whereas IPv6 is a 128-bit address.

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12y ago

It uses 32 bits.

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Q: How many bits are used in the ipv4 addressing scheme?
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32 bits in a IPv4 address


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32 bits. An IPv4 address looks like this: 192.168.1.1 Each number can only go from 0 to 255. That makes for 256 possible choices for each number. And 28=256, meaning that there can only be 8 bits per number. So, 8+8+8+8=32, which means that there are a total of 32 bits in an IPv4 address.


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