How many bytes are required to store an address of an integer?

Answer 1

32 bits or 4 bytes.

This depends heavily on the processor architecture your computer uses, AND the programming language you are using.

Typically, an integer is 1 word in length, however that processor architecture defines "word". That could be 32-bits (4 bytes), 64-bits (8 bytes), 8-bits (1 byte), or even 9 bits (in certain old computers).

Answer 2

A hexadecimal digit can store 16 different values, which requires 4 bits or 1/2 byte. Since we often can't split bytes in half, this would be rounded up to 1 byte to store 2 hexadecimal digits.

Answer 3

A float requires 32 bits in Java, which is equivalent to 4 bytes.

Answer 4

Try this:

printf ("In this platform an integer pointer uses %d bytes\n", (int) sizeof (int *));

Answer 5

Try this:

printf ("In this platform an integer uses %d bytes\n", (int) sizeof (int));

Answer 6

Depends how long the number is because if it is 0 or 1 your a beslubbering boil-brained whey-face!

Answer 7

Use sizeof(int) to find out. Most likely 2, 4 or 8.

Answer 8

sizeof (int). Often two or four.

Answer 9

4