7,893,600 (seven million, 8 hundred ninety-three thousand, 600) combinations in English.
The number of combinations of the letters TELEPHONE is 9 factorial, or 362,880. From that, however, we have to divide by 4 to account for the E being repeated twice, so the number of distinct combinations is 90,720.
9! (nine factorial)However, since the S is repeated 4 times you need to divide that by 16, and since the E is repeated once, you need to divide that by 2. The final result, which is the number of distinctcombinations of the letters POSSESSES is 11340.
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
Since no letters are repeated in the word prime, you can arrange the letters in the word prime 5! ways, or 120 ways.
This is really a question about permuations with repeated elements. The formula for that is n!/a! b!... where a, b,.. are repeated So we have 6 elelments with each repeated 2 times. so the number is. 6!/2!2!2! This is 6x5x4x3x2x1/ 23 so we can cancel out the 4 and the 2. 6x5x3=90 So 90 different numbers.
20
you can make 6
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
The number of combinations of the letters TELEPHONE is 9 factorial, or 362,880. From that, however, we have to divide by 4 to account for the E being repeated twice, so the number of distinct combinations is 90,720.
Without allowing repeated letters there are 38 possible words:GEEGHEEGLEELEGEREGERGREEVERGEHEELHELVEHEREEELLEELEERREELELVERLEVERREVELEREREEEVERVEEREVEVEEGELLEGERGREGVEGHEEHHERLLEHRHERELLEVERREREV
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
256 iThink * * * * * It depends on combinations of how many. There is 1 combination of 4 letters out of 4, 4 combinations of 3 letters out of 4, 6 combinations of 2 letters out of 4, 4 combinations of 1 letter out of 4. Than makes 15 (= 24-1) in all. Well below the 256 suggested by the previous answer.
4
Because there are 7 letters that don't repeat, 7X6X5X4=840 combinations. To give you an idea of how to solve the problem, if there had been 9 letters and you wanted to make combinations of 3 letters, you would multiply: 9X8X7=504