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How many different 4-person subcommittees can be formed from a club having 12 members?
Wiki User
∙ 15y ago
12C4
= (12!)/[(12 - 4)!4!]
= (12!)/(8!4!)
= (12 x 11 x 10 x 9 x 8!)/(8! x 4 x 3 x 2 x 1) Simplify 8! with 8!, 12 with 4 x 3, 10 with 2
= 11 x 5 x 9
= 495
Or you can use the graphing calculator:
press 12, MATH, go with the right arrow to PRB, press 3 for nCr, ENTER
Wiki User
∙ 15y ago
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